Question

函数y=sinαcosα-cos²α的最小正周期为______．

Answer 1

∵y=sinαcosα-cos²α=

1

2

sin2α -

1

2

cos2α-

1

2

=

2

2

sin(2α-

π

4

)-

1

2

，
∴三角函数的最小正周期是T=

2π

2

=π
故答案为：π