ÌâÄ¿ÄÚÈÝ
£¨1£©Î¢Á£XZ32-µÄÖÐÐÄÔ×ÓÔÓ»¯ÀàÐÍΪ
£¨2£©R»ù̬Ô×Óµç×ÓÅŲ¼Ê½Îª
£¨3£©Ò»ÖÖÐÂÐͳ¬µ¼¾§ÌåµÄ¾§°ûÈçͼËùʾ£¬Ôò¸Ã¾§ÌåµÄ»¯Ñ§Ê½Îª
£¨4£©RµÄÇâÑõ»¯ÎïÄÜÈÜÓÚº¬XY-Àë×ÓµÄÈÜÒºÉú³ÉÒ»ÖÖÅäÀë×Ó[R£¨XY£©4]2-£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
¿¼µã£º¾§°ûµÄ¼ÆËã,ÔªËØµçÀëÄÜ¡¢µç¸ºÐԵĺ¬Òå¼°Ó¦ÓÃ,λÖýṹÐÔÖʵÄÏ໥¹ØÏµÓ¦ÓÃ,Ô×Ó¹ìµÀÔÓ»¯·½Ê½¼°ÔÓ»¯ÀàÐÍÅжÏ
רÌ⣺
·ÖÎö£ºÔªËØX¡¢Y¡¢Z¡¢W¡¢Q¾ùΪ¶ÌÖÜÆÚÔªËØ£¬Ô×ÓÐòÊýÒÀ´ÎÔö´ó£®X»ù̬Ô×ÓºËÍâµç×Ó·Ö²¼ÔÚ3¸öÄܼ¶£¬ÇÒ¸÷Äܼ¶µç×ÓÊýÏàµÈ£¬Æäµç×ÓÅŲ¼Îª1s22s22p2£¬ÔòXΪC£»ZÊǵؿÇÖк¬Á¿×î¶àµÄÔªËØ£¬ÔòZΪO£¬ËùÒÔYΪN£»WÊǵ縺ÐÔ×î´óµÄÔªËØ£¬ÔòWΪF£¬ÔªËØQµÄºËµçºÉÊýµÈÓÚY¡¢WÔ×Ó×îÍâ²ãµç×ÓÊýÖ®ºÍ£¬ÔòQµÄºËµçºÉÊýΪ5+7=12£¬ÔòQΪMg£»ÁíÓÐRÔªËØÎ»ÓÚÖÜÆÚ±íµÚ4ÖÜÆÚµÚVIII×壬¼Û²ãµç×ÓÖÐÓÐÁ½¸öδ³É¶Ôµç×Ó£¬µç×ÓÅŲ¼Îª1s22s22p63s23p63d84s2£¬ÔòRΪNiÔªËØ£¬ÒÔ´ËÀ´½â´ð£®
½â´ð£º
½â£ºÔªËØX¡¢Y¡¢Z¡¢W¡¢Q¾ùΪ¶ÌÖÜÆÚÔªËØ£¬Ô×ÓÐòÊýÒÀ´ÎÔö´ó£®X»ù̬Ô×ÓºËÍâµç×Ó·Ö²¼ÔÚ3¸öÄܼ¶£¬ÇÒ¸÷Äܼ¶µç×ÓÊýÏàµÈ£¬Æäµç×ÓÅŲ¼Îª1s22s22p2£¬ÔòXΪC£»ZÊǵؿÇÖк¬Á¿×î¶àµÄÔªËØ£¬ÔòZΪO£¬ËùÒÔYΪN£»WÊǵ縺ÐÔ×î´óµÄÔªËØ£¬ÔòWΪF£¬ÔªËØQµÄºËµçºÉÊýµÈÓÚY¡¢WÔ×Ó×îÍâ²ãµç×ÓÊýÖ®ºÍ£¬ÔòQµÄºËµçºÉÊýΪ5+7=12£¬ÔòQΪMg£»ÁíÓÐRÔªËØÎ»ÓÚÖÜÆÚ±íµÚ4ÖÜÆÚµÚVIII×壬¼Û²ãµç×ÓÖÐÓÐÁ½¸öδ³É¶Ôµç×Ó£¬µç×ÓÅŲ¼Îª1s22s22p63s23p63d84s2£¬ÔòRΪNiÔªËØ£¬
£¨1£©Î¢Á£CO32-µÄÖÐÐÄÔ×Ó¼Ûµç×ÓÊý4+
=4£¬Îªsp3ÔÓ»¯£¬»¯ºÏÎïNF3µÄ¿Õ¼ä¹¹ÐÍÓë°±ÆøÏàËÆ£¬ÎªÈý½Ç×¶ÐΣ¬¹Ê´ð°¸Îª£ºsp3£»Èý½Ç×¶ÐΣ»
£¨2£©RµÄÔ×ÓÐòÊýΪ28£¬Æä»ù̬Ô×Óµç×ÓÅŲ¼Ê½Îª1s22s22p63s23p63d84s2»ò[Ar]3d84s2£¬NµÄ2pµç×Ó°ëÂúΪÎȶ¨½á¹¹£¬·Ç½ðÊôÐÔÇ¿µÄµÚÒ»µçÀëÄÜ´ó£¬ÔòÔªËØX¡¢Y¡¢ZµÄµÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòΪN£¾O£¾C£¬¹Ê´ð°¸Îª£º1s22s22p63s23p63d84s2»ò[Ar]3d84s2£»N£¾O£¾C£»
£¨3£©MgλÓÚ¶¥µã£¬¸öÊýΪ8¡Á
=1£¬CλÓÚÌåÐÄ£¬¸öÊýΪ1£¬NiλÓÚÃæÐÄ£¬¸öÊýΪ6¡Á
=3£¬Ôò¾§ÌåµÄ»¯Ñ§Ê½ÎªMgCNi3»òMg Ni3C£¬QÓëR×î½ü¾àÀëÔÚÃæÉÏ£¬1¸öQ½ôÁÚRÔ×ӵĸöÊýΪ3¡Á8¡Á
=12£¬¹Ê´ð°¸Îª£ºMgCNi3»òMg Ni3C£»12£»
£¨4£©RµÄÇâÑõ»¯ÎïÄÜÈÜÓÚº¬XY-Àë×ÓµÄÈÜÒºÉú³ÉÒ»ÖÖÅäÀë×Ó[R£¨XY£©4]2-£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽÊÇNi£¨OH£©2+4CN-=[Ni£¨CN£©4]2-+2OH-£¬ÈõËáHXY·Ö×Ó£¬½á¹¹Ê½ÎªH-C¡ÔN£¬µ¥¼üΪ¦Ò¼ü£¬Èý¼üÖÐÓÐ1¸ö¦Ò¼ü¡¢2¸ö¦Ð¼ü£¬Ôò´æÔڵĦҼüÓë¦Ð¼üµÄÊýĿ֮±ÈΪ1£º1£¬
¹Ê´ð°¸Îª£ºNi£¨OH£©2+4CN-=[Ni£¨CN£©4]2-+2OH-£»1£º1£®
£¨1£©Î¢Á£CO32-µÄÖÐÐÄÔ×Ó¼Ûµç×ÓÊý4+
| 4+2-2¡Á3 |
| 2 |
£¨2£©RµÄÔ×ÓÐòÊýΪ28£¬Æä»ù̬Ô×Óµç×ÓÅŲ¼Ê½Îª1s22s22p63s23p63d84s2»ò[Ar]3d84s2£¬NµÄ2pµç×Ó°ëÂúΪÎȶ¨½á¹¹£¬·Ç½ðÊôÐÔÇ¿µÄµÚÒ»µçÀëÄÜ´ó£¬ÔòÔªËØX¡¢Y¡¢ZµÄµÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòΪN£¾O£¾C£¬¹Ê´ð°¸Îª£º1s22s22p63s23p63d84s2»ò[Ar]3d84s2£»N£¾O£¾C£»
£¨3£©MgλÓÚ¶¥µã£¬¸öÊýΪ8¡Á
| 1 |
| 8 |
| 1 |
| 2 |
| 1 |
| 2 |
£¨4£©RµÄÇâÑõ»¯ÎïÄÜÈÜÓÚº¬XY-Àë×ÓµÄÈÜÒºÉú³ÉÒ»ÖÖÅäÀë×Ó[R£¨XY£©4]2-£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽÊÇNi£¨OH£©2+4CN-=[Ni£¨CN£©4]2-+2OH-£¬ÈõËáHXY·Ö×Ó£¬½á¹¹Ê½ÎªH-C¡ÔN£¬µ¥¼üΪ¦Ò¼ü£¬Èý¼üÖÐÓÐ1¸ö¦Ò¼ü¡¢2¸ö¦Ð¼ü£¬Ôò´æÔڵĦҼüÓë¦Ð¼üµÄÊýĿ֮±ÈΪ1£º1£¬
¹Ê´ð°¸Îª£ºNi£¨OH£©2+4CN-=[Ni£¨CN£©4]2-+2OH-£»1£º1£®
µãÆÀ£º±¾Ì⿼²é½Ï×ۺϣ¬Éæ¼°ÔªËØµÄÍÆ¶Ï¡¢¾§°û¼ÆËã¡¢µç×ÓÅŲ¼µÈ£¬×¢ÖØ¸ßÆµ¿¼µãµÄѵÁ·£¬²àÖØÎ»Öᢽṹ¡¢ÐÔÖʼ°Ô×ӽṹÓë¾§ÌåµÄ·ÖÎöÓëÍÆ¶ÏÄÜÁ¦µÄ×ۺϿ¼²é£¬ÌâÄ¿ÄѶÈÖеȣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Ïò10mL 1.5mol/LµÄÁòËáÂÁÈÜÒº¼ÓÈë30mL NaOHÈÜÒº£¬³ä·Ö·´Ó¦ºóµÃµ½1.56g³Áµí£¬ÔòNaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ£¨¡¡¡¡£©
| A¡¢1mol/L |
| B¡¢2mol/L |
| C¡¢5mol/L |
| D¡¢3.3mol/L |
X¡¢Y¡¢ZÈýÖÖ¶ÌÖÜÆÚ·Ç½ðÊôÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÈçͼËùʾ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

| A¡¢Ô×ӵİ뾶£ºY´óÓÚX |
| B¡¢Ç⻯ÎïµÄÎȶ¨ÐÔ£ºX´óÓÚY |
| C¡¢×î¸ß¼ÛÑõ»¯ÎïË®»¯ÎïµÄËáÐÔ£ºZÇ¿ÓÚY |
| D¡¢ZÔ×Ó±ÈYÔ×Ó¶àÒ»¸öµç×Ó²ã |