ÌâÄ¿ÄÚÈÝ

£¨10·Ö£©£¨1£©³£ÎÂÏÂÎïÖʵÄÁ¿Å¨¶ÈÏàͬµÄa  HF¡¢b NH3¡¤H2O¡¢c  H2SÈÜÒº£¬µçÀë³£Êý·Ö±ðΪ7.2¢ª10-4¡¢5.6¢ª10-10ºÍK1=9.1¢ª10-8,K2=1.1¢ª10-12¡£
¢Ùµç½âÖʵÄÇ¿Èõ˳ÐòΪ£ß___________£ß(Ìîa¡¢b¡¢c)£¬¢ÚÇâÀë×ÓŨ¶È×îСµÄÊǣߣߣß(Ìîa¡¢b¡¢c)¡£
£¨2£©1L1mol/LH2SO4ÈÜÒºÓë2L1mol/LNaOHÈÜÒºÍêÈ«·´Ó¦£¬·Å³ö114.6kJµÄÈÈÁ¿£¬ÓÉ´ËÍÆÖªH2SO4ÓëNaOH·´Ó¦µÄÖкÍÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ___________________________¡£
(3)Ïò1L1mol/LµÄNaOHÈÜÒºÖмÓÈëÏÂÁÐÎïÖÊ£º¢ÙŨH2SO4£»¢ÚÏ¡ÏõË᣻¢ÛÏ¡´×ËᣬǡºÃÍêÈ«·´Ó¦µÄÈÈЧӦ¡÷H1¡¢¡÷H2¡¢¡÷H3µÄ´óС¹ØÏµÎª             ¡£
(4)ÒÑÖªÏÂÁз´Ó¦µÄ·´Ó¦ÈÈ:
¢ÙCH3COOH(l) + 2O2 (g)= 2CO2 (g)+ 2H2O(l) ¡÷H=-870.3kJ¨Mmol
¢ÚC(S) + O2 (g)= CO2 (g)   ¡÷H=-393.5kJ¨Mmol
¢Û2C(S) + 2H2 (g) + O2 (g)= CH3COOH(l)   ¡÷H=-488.3kJ¨Mmol
Çëд³öH2ȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ                               ¡£

(1) ¢Ùacb £¨2 ·Ö£© ¢Úb£¨ 2·Ö£©
(2) 1/2H2SO4(aq) +NaOH(aq)=1/2Na2SO4(aq)+H2O(l)£»¦¤H=-57.3 kJ/mol£¨2 ·Ö£©
(3)¦¤H3 >¦¤H2>¦¤H£¨ 2·Ö£©(4)H2 (g) +1/2 O2 (g)= H2O(l) ¡÷H=-285.8kJ¨Mmol£¨2 ·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø