Question

7£®µªÔªËصÄÇ⻯ÎïºÍÑõ»¯ÎïÔÚ¹¤ÒµÉú²úºÍ¹ú·À½¨ÉèÖж¼Óй㷺ӦÓ㬻شðÏÂÁÐÎÊÌ⣺
£¨1£©µªÔªËØÔ­×ÓµÄL²ãµç×ÓÊýΪ5£»ëÂÖеĻ¯Ñ§¼üÀàÐÍΪ¹²¼Û¼ü£®
£¨2£©ë¿É×÷Ϊ»ð¼ý·¢¶¯»úµÄȼÁÏ£¬ÓëÑõ»¯¼ÁN₂O₄·´Ó¦Éú³ÉN₂ºÍË®ÕôÆø£®
ÒÑÖª£º
¢ÙN₂£¨g£©+2O₂£¨g£©=N₂O₄£¨l£©£»¡÷H₁=-19.5kJ•mol^-1
¢ÚN₂H₄£¨l£©+O₂£¨g£©=N₂£¨g£©+2H₂O£¨g£©£»¡÷H₂=-534.2kJ•mol^-1
д³öëºÍN₂O₄·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ2N₂H₄£¨l£©+N₂O₄£¨l£©=3N₂£¨g£©+4H₂O£¨g£©¡÷H=-1048.9 kJ•mol^-1£»
£¨3£©ÒÑÖªH₂O£¨l£©=H₂O£¨g£©£»¡÷H₃=+44kJ•mol^-1£¬Ôò±íʾëÂȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪN₂H₄£¨l£©+O₂£¨g£©=N₂£¨g£©+2H₂O£¨l£©¡÷H=-622.2 kJ•mol^-1£®

Answer 1

·ÖÎö £¨1£©µªÔªËØÔ­×ÓÐòÊýΪ7£¬¸ù¾Ý¹¹ÔìÔ­Àí£¬ÅÅÂúK²ãÔÙÅÅL²ã£¬K²ã2¸öµç×Ó£¬L²ãΪ5¸öµç×Ó£¬ëÂÊǹ²¼Û»¯ºÏÎﵪԭ×ÓºÍÇâÔ­×ÓÐγɹ²¼Û¼ü£¬µªÔ­×Ӻ͵ªÔ­×Ó¼äÒ²Ðγɹ²¼Û¼ü£»
£¨2£©ÒÀ¾Ý¸Ç˹¶¨ÂÉ£º¢Ú¡Á2-¢ÙµÃµ½£º2N₂H₄£¨l£©++N₂O₄£¨l£©=3N₂£¨g£©+4H₂O£¨g£©£¬·´Ó¦ÈÈÓ뻯ѧ¼ÆÁ¿Êý³ÉÕý±È£»
£¨3£©È¼ÉÕÈÈÊÇÖ¸1mol¿ÉȼÎïÍêȫȼÉÕÉú³ÉÎȶ¨µÄÑõ»¯ÎïʱËù·Å³öµÄÈÈÁ¿£¬¸ù¾ÝȼÉÕÈȵĸÅÄ½áºÏ¸Ç˹¶¨Âɽâ´ð£®

½â´ð ½â£º£¨1£©µªÔªËØÔ­×ÓÐòÊýΪ7£¬¸ù¾Ý¹¹ÔìÔ­Àí£¬ÅÅÂúK²ãÔÙÅÅL²ã£¬K²ã2¸öµç×Ó£¬L²ãΪ5¸öµç×Ó£¬ëÂÊǹ²¼Û»¯ºÏÎﵪԭ×ÓºÍÇâÔ­×ÓÐγɹ²¼Û¼ü£¬µªÔ­×Ӻ͵ªÔ­×Ó¼äÒ²Ðγɹ²¼Û¼ü£¬½á¹¹Ê½Îª£º£¬
¹Ê´ð°¸Îª£º5£»¹²¼Û¼ü£»
£¨2£©£©¢ÙN₂£¨g£©+2O₂£¨g£©=N₂O₄£¨l£©¡÷H₁=-19.5kJ?mol^-1
¢ÚN₂H₄£¨l£©+O₂ £¨g£©=N₂£¨g£©+2H₂O£¨g£©¡÷H₂=-534.2kJ•mol^-1
¸ù¾Ý¸Ç˹¶¨ÂÉд³öëºÍN₂O₄·´Ó¦µÄÈÈ»¯Ñ§·½³Ì£º¢Ú¡Á2-¢ÙµÃµ½£º2N₂H₄£¨l£©++N₂O₄£¨l£©=3N₂£¨g£©+4H₂O£¨g£©¡÷H=£¨-534.2£©¡Á2-£¨-19.5£©kJ•mol^-1=-1048.9 kJ•mol^-1£»
¹Ê´ð°¸Îª£º2N₂H₄£¨l£©+N₂O₄£¨l£©=3N₂£¨g£©+4H₂O£¨g£©¡÷H=-1048.9 kJ•mol^-1£»
£¨3£©È¼ÉÕÈÈ£¬Ö¸Éú³ÉµÄË®±ØÐëΪҺ̬£¬¿ÉȼÎï±ØÐëΪ1mol£®
ÓÉ·´Ó¦¢ÙN₂H₄£¨l£©+O₂ £¨g£©=N₂£¨g£©+2H₂O£¨g£©¡÷H₂=-534.2kJ•mol^-1
¢ÚH₂O£¨l£©¨TH₂O£¨g£©¡÷H₃=+44kJ•mol^-1
½«¢Ù-2¡Á¢Ú¿ÉµÃ£ºN₂H₄£¨l£©+O₂ £¨g£©=N₂£¨g£©+2H₂O£¨l£©¡÷H₂=-622.2kJ•mol^-1
¹Ê´ð°¸Îª£ºN₂H₄£¨l£©+O₂ £¨g£©=N₂£¨g£©+2H₂O£¨l£©¡÷H₂=-622.2kJ•mol^-1£®

µãÆÀ ±¾Ì⿼²éÁËÔ­×ÓºËÍâµç×ÓÅŲ¼¡¢ëµĻ¯Ñ§¼ü¡¢ÈÈ»¯Ñ§·½³Ìʽ¡¢¸Ç˹¶¨ÂɵÄÓ¦ÓõÈ֪ʶ£¬×¢Òâ¸Ç˹¶¨ÂɵÄÊìÁ·Ó¦Óã¬Îª¸ßƵ¿¼µã£¬ÌâÄ¿ÄѶÈÖеȣ®