ÌâÄ¿ÄÚÈÝ
15£®£¨1£©¼×ÍéÓëË®ÕôÆø·´Ó¦£¬±»Ñõ»¯µÄÔªËØÊÇC£¨Ì¼£©£¬µ±Éú³É±ê×¼×´¿öÏÂ35.84LºÏ³ÉÆøÊ±×ªÒÆµç×ÓµÄÎïÖʵÄÁ¿ÊÇ2.4mol£®
£¨2£©½«2mol CH4ºÍ5mol H2O£¨g£©Í¨ÈëÈÝ»ýΪ100LµÄ·´Ó¦ÊÒ£¬CH4µÄƽºâת»¯ÂÊÓëζȡ¢Ñ¹Ç¿µÄ¹ØÏµÈçͼ£®
¢Ù´ïµ½AµãËùÐèµÄʱ¼äΪ5min£¬Ôòv£¨H2£©=0.006mol•L-1•min-1£¬100¡æÊ±Æ½ºâ³£ÊýK=6.75¡Á10-4mol2•L-2£®
¢ÚͼÖеÄP1£¼P2£¨Ìî¡°£¼¡±¡¢¡°£¾¡±»ò¡°=¡±£©£¬A¡¢B¡¢CÈýµãµÄƽºâ³£ÊýKA¡¢KB¡¢KCµÄ´óС¹ØÏµÊÇKC£¾KB£¾KA£®
£¨3£©ºÏ³ÉÆøÓÃÓںϳɰ±ÆøÊ±Ðè³ýÈ¥CO£¬·¢Éú·´Ó¦CO£¨g£©+H2O£¨g£©?CO2£¨g£©+H2£¨g£©¡÷H£¼0£¬ÏÂÁдëÊ©ÖÐÄÜʹ$\frac{n£¨C{O}_{2}£©}{n£¨{H}_{2}O£©}$Ôö´óµÄAC£¨Ñ¡Ìî±àºÅ£©£®
A£®½µµÍÎÂ¶È B£®ºãκãÈÝϳäÈëHe£¨g£©
C£®½«H2´ÓÌåϵÖзÖÀë D£®ÔÙͨÈëÒ»¶¨Á¿µÄË®ÕôÆø
¿ÉÓÃ̼Ëá¼ØÈÜÒºÎüÊÕÉú³ÉµÄCO2£¬³£ÎÂÏÂpH=10µÄ̼Ëá¼ØÈÜÒºÖÐË®µçÀëµÄOH-µÄÎïÖʵÄÁ¿Å¨¶ÈΪ1¡Á10-4mol•L-1£¬³£ÎÂÏ£¬0.1mol•L-1KHCO3ÈÜÒºpH£¾8£¬ÔòÈÜÒºÖÐc£¨H2CO3£©£¾c£¨CO32-£©£¨Ìî¡°£¾¡±¡¢¡°=¡±»ò¡°£¼¡±£©£®
·ÖÎö £¨1£©¸Ã·´Ó¦ÖÐCÔªËØ»¯ºÏ¼ÛÓÉ-4¼Û±äΪ+2¼Û¡¢HÔªËØ»¯ºÏ¼ÛÓÉ+1¼Û±äΪ0¼Û£¬Ê§µç×Ó»¯ºÏ¼ÛÉý¸ßµÄÔªËØ±»Ñõ»¯£»µ±Éú³É±ê×¼×´¿öÏÂ35.84LºÏ³ÉÆøÊ±£¬Éú³Én£¨CO£©=$\frac{35.84L}{22.4L/mol}$=0.4mol£¬¸ù¾ÝCÔªËØ»¯ºÏ¼Û±ä»¯È·¶¨×ªÒƵç×ÓµÄÎïÖʵÄÁ¿£»
£¨2£©¢Ù¸ù¾Ýv=$\frac{\frac{¡÷n}{V}}{¡÷t}$¼ÆËã¼×ÍéµÄ·´Ó¦ËÙÂÊ£¬ÔÙ¸ù¾Ýͬһ¿ÉÄæ·´Ó¦¡¢Í¬Ò»Ê±¼ä¶ÎÄÚ¸öÎïÖʵķ´Ó¦ËÙÂÊÖ®±ÈµÈÓÚÆä¼ÆÁ¿ÊýÖ®±È¼ÆËãÇâÆøµÄ·´Ó¦ËÙÂÊ£»
»¯Ñ§Æ½ºâ³£ÊýK=$\frac{c£¨CO£©£®{c}^{3}£¨{H}_{2}£©}{c£¨C{H}_{4}£©£®c£¨{H}_{2}O£©}$£»
¢ÚÏàͬÆäËüÌõ¼þÏ£¬Ôö´óѹǿ£¬Æ½ºâÏòÄæ·´Ó¦·½ÏòÒÆ¶¯£¬¼×ÍéµÄת»¯Îª¼õС£»»¯Ñ§Æ½ºâ³£ÊýÖ»ÓëζÈÓйأ¬Éý¸ßζȣ¬¼×ÍéµÄת»¯ÂÊÔö´ó£¬ÔòÕý·´Ó¦ÊÇÎüÈÈ·´Ó¦£¬Î¶ÈÔ½¸ß£¬»¯Ñ§Æ½ºâ³£ÊýÔ½´ó£»
£¨3£©ÄÜʹ$\frac{n£¨C{O}_{2}£©}{n£¨{H}_{2}O£©}$Ôö´ó£¬¸Ã·´Ó¦Ó¦¸ÃÏòÕý·´Ó¦·½ÏòÒÆ¶¯µ«²»ÄÜͨ¹ýÔö´óË®ÕôÆøµÄÎïÖʵÄÁ¿ÊµÏÖ£»
Ë®µçÀëµÄOH-µÄÎïÖʵÄÁ¿Å¨¶È=$\frac{1{0}^{-14}}{1{0}^{-pH}}$£»³£ÎÂÏ£¬0.1mol•L-1 KHCO3ÈÜÒºpH£¾8£¬ËµÃ÷̼ËáÇâ¸ùÔÚË®½â³Ì¶È´óÓÚµçÀë³Ì¶È£®
½â´ð ½â£º£¨1£©¸Ã·´Ó¦ÖÐCÔªËØ»¯ºÏ¼ÛÓÉ-4¼Û±äΪ+2¼Û¡¢HÔªËØ»¯ºÏ¼ÛÓÉ+1¼Û±äΪ0¼Û£¬Ê§µç×Ó»¯ºÏ¼ÛÉý¸ßµÄÔªËØ±»Ñõ»¯£¬ËùÒÔCÔªËØ±»Ñõ»¯£»µ±Éú³É±ê×¼×´¿öÏÂ35.84LºÏ³ÉÆøÊ±£¬Éú³É£¨CO£©=$\frac{35.84L}{22.4L/mol}$=0.4mol£¬Ôò×ªÒÆµç×ÓµÄÎïÖʵÄÁ¿=0.4mol¡Á[2-£¨-4£©]=2.4mol£¬
¹Ê´ð°¸Îª£ºC£¨Ì¼£©£»2.4mol£»
£¨2£©¢Ù¼×ÍéµÄ·´Ó¦ËÙÂÊ=$\frac{\frac{2mol¡Á0.5}{100L}}{5min}$=0.002mol/£¨L£®min£©£¬Í¬Ò»¿ÉÄæ·´Ó¦¡¢Í¬Ò»Ê±¼ä¶ÎÄÚ¸öÎïÖʵķ´Ó¦ËÙÂÊÖ®±ÈµÈÓÚÆä¼ÆÁ¿ÊýÖ®±È£¬ÔòÇâÆøµÄ·´Ó¦ËÙÂÊ=3¡Á0.002mol/£¨L£®min£©=0.006mol/£¨L£®min£©£»
100¡æÊ±£¬c£¨CH4£©=$\frac{2mol¡Á£¨1-0.5£©}{100L}$=0.01mol/L£¬c£¨H2O£©=$\frac{5mol-2mol¡Á£¨1-0.5£©}{100L}$=0.04mol/L£¬
c£¨CO£©=$\frac{2mol¡Á0.5}{100L}$=0.01mol/L£¬c£¨H2£©=3c£¨CO£©=0.03mol/L£¬»¯Ñ§Æ½ºâ³£ÊýK=$\frac{c£¨CO£©£®{c}^{3}£¨{H}_{2}£©}{c£¨C{H}_{4}£©£®c£¨{H}_{2}O£©}$=$\frac{0.01¡Á£¨0.03£©3}{0.01¡Á0.04}$=6.75¡Á10-4£¬
¹Ê´ð°¸Îª£º0.006mol•L-1•min-1£»6.75¡Á10-4 mol2•L-2£»
¢Ú¸ù¾ÝͼÏóÖª£¬Ôö´óѹǿ£¬Æ½ºâÏòÄæ·´Ó¦·½ÏòÒÆ¶¯£¬Ôò¼×ÍéµÄת»¯ÂʽµµÍ£¬ËùÒÔP1£¼P2£»
Éý¸ßζȣ¬¼×ÍéµÄת»¯ÎªÔö´ó£¬ËµÃ÷Õý·´Ó¦ÊÇÎüÈÈ·´Ó¦£¬Î¶ÈÔ½¸ß£¬Æ½ºâ³£ÊýÔ½´ó£¬ËùÒÔKC£¾KB£¾ KA£¬
¹Ê´ð°¸Îª£º£¼£»KC£¾KB£¾ KA£»
£¨3£©A£®½µµÍζȣ¬Æ½ºâÏòÕý·´Ó¦·½ÏòÒÆ¶¯£¬ÔòÄÜʹ$\frac{n£¨C{O}_{2}£©}{n£¨{H}_{2}O£©}$Ôö´ó£¬¹ÊÕýÈ·£»
B£®ºãκãÈÝϳäÈëHe£¨g£©£¬·´Ó¦ÎïºÍÉú³ÉÎïŨ¶È²»±ä£¬Ôòƽºâ²»Ò»¶¨£¬Ôò$\frac{n£¨C{O}_{2}£©}{n£¨{H}_{2}O£©}$²»±ä£¬¹Ê´íÎó£»
C£®½«H2´ÓÌåϵÖзÖÀ룬ƽºâÏòÕý·´Ó¦·½ÏòÒÆ¶¯£¬Ôò$\frac{n£¨C{O}_{2}£©}{n£¨{H}_{2}O£©}$Ôö´ó£¬¹ÊÕýÈ·£»
D£®ÔÙͨÈëÒ»¶¨Á¿µÄË®ÕôÆø£¬Æ½ºâÏòÕý·´Ó¦·½ÏòÒÆ¶¯£¬µ«Ë®×ª»¯µÄÎïÀíÁ¿Ô¶Ô¶Ð¡ÓÚ¼ÓÈëµÄÎïÀíÁ¿£¬ËùÒÔÄÜʹ$\frac{n£¨C{O}_{2}£©}{n£¨{H}_{2}O£©}$¼õС£¬¹Ê´íÎó£»
¹ÊÑ¡£ºAC£»
¿ÉÓÃ̼Ëá¼ØÈÜÒºÎüÊÕÉú³ÉµÄCO2£¬³£ÎÂÏÂpH=10µÄ̼Ëá¼ØÈÜÒºÖÐË®µçÀëµÄc£¨OH-£©=$\frac{1{0}^{-14}}{1{0}^{-10}}$mol/L=1¡Á10-4 mol•L-1£»³£ÎÂÏ£¬0.1mol•L-1 KHCO3ÈÜÒºpH£¾8£¬ÔòÈÜÒºÖÐ̼ËáÇâ¸ùÀë×ÓË®½â³Ì¶È´óÓÚµçÀë³Ì¶È£¬ËùÒÔc£¨H2CO3£©£¾c£¨CO32-£©£¬¹Ê´ð°¸Îª£ºAC£» 1¡Á10-4 mol•L-1£»£¾£®
µãÆÀ ±¾Ì⿼²éÁËת»¯ÂÊÓëζȺÍѹǿµÄ¹ØÏµ¡¢»¯Ñ§Æ½ºâÒÆ¶¯µÄÓ°ÏìÒòËØ¡¢ÑÎÀàË®½âµÈ֪ʶµã£¬»á¸ù¾ÝͼÏóÖÐζȡ¢Ñ¹Ç¿Î¶ȷ´Ó¦ÈÈ¡¢Æ½ºâÒÆ¶¯·½Ïò£¬×¢Ò⻯ѧƽºâ³£ÊýÖ»ÓëζÈÓйأ¬×¢Ò⣨3£©ÖÐBDÑ¡ÏÈç¹ûºãѹÌõ¼þϳäÈëHe£¬Ôòƽºâ»á·¢ÉúÒÆ¶¯£¬µ«ºãÈÝÌõ¼þÏÂͨÈëHe£¬Ôòƽºâ²»Òƶ¯£¬ÎªÒ×´íµã£®
¢ÙNH3µÄÈÛ¡¢·Ðµã±ÈVA×åÆäËûÔªËØÇ⻯ÎïµÄÈÛ¡¢·Ðµã¸ß
¢ÚС·Ö×ӵĴ¼¡¢ôÈËá¿ÉÒÔºÍË®ÒÔÈÎÒâ±È»¥ÈÜ
¢ÛÁÚôÇ»ù±½¼×ËáµÄÈÛ¡¢·Ðµã±È¶ÔôÇ»ù±½¼×ËáµÄÈÛ¡¢·ÐµãµÍ
¢ÜË®·Ö×Ó¸ßÎÂÏÂÒ²ºÜÎȶ¨¢ÝË®·Ö×Ó½ÏÁò»¯Çâ·Ö×ÓÎȶ¨£®
| A£® | ¢Ù¢Ú¢Û¢Ü | B£® | ¢Ü¢Ý | C£® | ¢Û¢Ü¢Ý | D£® | ¢Ù¢Ú¢Û |
¢ñ£®¼õÉÙ¶þÑõ»¯Ì¼µÄÅÅ·ÅÊÇÒ»ÏîÖØÒª¿ÎÌ⣮Ñо¿±íÃ÷£¬C02¾´ß»¯¼ÓÇâ¿ÉºÏ³ÉµÍ̼´¼£ºCO2£¨g£©+3H2£¨g£©?CH3OH£¨g£©+H2O£¨g£©¡÷H¼¸ÖÖ»¯Ñ§¼üµÄ¼üÄÜÈç±íËùʾ
| »¯Ñ§¼ü | C=0 | H-H | C-C | C-H | 0-H | C-0 |
| ¼üÄÜ/kJ•mol-1 | 803 | 436 | 332 | 409 | 463 | 326 |
£¨2£©ÔÚ1.0LºãÈÝÃܱÕÈÝÆ÷ÖÐͶÈëlmolC02ºÍ2.75molH2·¢Éú¸Ã·´Ó¦£¬ÊµÑé²âµÃ²»Í¬Î¶ȼ°Ñ¹Ç¿Ï£¬Æ½ºâʱ¼××íµÄÎïÖʵÄÁ¿ÈçͼËùʾ£®
µ±Ñ¹Ç¿ÎªP2£¬Î¶ÈΪ512Kʱ£¬Ïò¸ÃÈÝÆ÷ÖÐͶÈë lmol CO2¡¢0.5mol H2¡¢2mol CH3OH¡¢0.6mol H20ʱ£¬Æ½ºâÏòÄæ·´Ó¦·½ÏòÒÆ¶¯£®
£¨3£©ÒÔCH3OH¡¢¿ÕÆø£¨02º¬Á¿20%£©¡¢KOHÈÜҺΪ ÔÁÏ£¬ÒÔʯīΪµç¼«¿ÉÖ±½Ó¹¹³ÉȼÁÏµç³Ø£¬Ôò¸Ãµç³ØµÄ¸º¼«·´Ó¦Ê½ÎªCH3OH+8OH--6e-=CO32-+6H2O£»Óøà µç³Øµç½â500mL 1mol/L CuSO4ÈÜÒº£¬µ±È¼ÁÏµç³ØÏûºÄ±ê¿öÏÂ56L¿ÕÆøÊ±£¬¼ÆËãÀíÂÛÉÏÁ½¼«µç½â²úÉúÆøÌåµÄ×ÜÎïÖʵÄÁ¿1mol£®
¢ò£®SO2Ò²ÊÇÒ»ÖÖ´óÆøÎÛȾÎ¿ÉÒÔÓú£Ë®´¦Àíº¬SO2µÄ·ÏÆø£¬º£Ë®ÖÐÖ÷ÒªÀë×ӵĺ¬Á¿ÈçÏ£º
| ³É·Ö | º¬Á¿/£¨mg/L£© | ³É·Ö | º¬Á¿£¨mg/L£© |
| Cl- | 18980 | Ca2+ | 400 |
| Na+ | 10560 | HCO3-£» | 142 |
| SO42- | 2560 | Mg2+ | 1272 |
ÒÑÖªKsp[Mg£¨OH£©2]=1.2¡Ál0-11 Ksp[Ca£¨OH£©2]=5.5¡Á10-6
£¨2£©´¦Àí¹ýµÄ·ÏÆøÖÐS02µÄº¬Á¿¿ÉÒÔͨ¹ýµâÁ¿·¨À´²â¶¨£®Óõ½µÄÊÔ¼ÁÓУº0£®l mol•LµÄµâ±ê×¼ÈÜÒº£¬µí·ÛÈÜÒº£®µ±°Ñ´¦ÀíºóµÄ·ÏÆøÒÔÿ·ÖÖÓaL£¨±ê¿öÏ£©µÄÁ÷ËÙͨÈëµ½lOOmLº¬Óеí·ÛµÄµâ±ê×¼ÒºÖУ¬t min´ïµ½µÎ¶¨Öյ㣮µÎ¶¨ÖÕµãµÄÏÖÏóΪÈÜÒºÀ¶É«ÍÊÈ¥£¬ÇÒ°ë·ÖÖÓ²»»Ö¸´ÑÕÉ«¼ÆËã¸Ã´¦ÀíÆøÖÐSO2µÄº¬Á¿$\frac{0.224}{at}$£¨Óú¬a£¬tµÄʽ×Ó±íʾ£©
| A£® | ·´Ó¦¹ý³ÌÖУ¬ÈôÔö´óѹǿÄÜÌá¸ßSiCl4µÄת»¯ÂÊ | |
| B£® | Èô·´Ó¦¿ªÊ¼Ê±SiCl4Ϊ1mol£¬Ôò´ïµ½Æ½ºâʱ£¬ÎüÊÕÈÈÁ¿ÎªQkJ | |
| C£® | ·´Ó¦ÖÁ4minʱ£¬ÈôHClµÄŨ¶ÈΪ0.12mol•L-1£¬ÔòH2µÄ·´Ó¦ËÙÂÊΪ£º0.015mol/£¨L•min£© | |
| D£® | µ±·´Ó¦ÎüÊÕÈÈÁ¿Îª0.025QkJʱ£¬Éú³ÉµÄHClͨÈë100mL1mol•L-1µÄNaOHÈÜҺǡºÃ·´Ó¦ |
£¨1£©ÒÑ֪̼µÄÆø»¯·´Ó¦ÔÚ²»Í¬Î¶ÈÏÂÆ½ºâ³£ÊýµÄ¶ÔÊýÖµ£¨lgK£©ÈçÏÂ±í£º
| Æø»¯·´Ó¦Ê½ | 1gK | ||
| 700K | 900K | 1200K | |
| C£¨s£©+H2O£¨g£©=CO£¨g£©+H2£¨g£© | -2.64 | -0.39 | 1.58 |
| C£¨s£©+2H2O£¨g£©=CO2£¨g£©+2H2£¨g£© | -1.67 | -0.03 | 1.44 |
£¨2£©ÒµÉϺϳɼ״¼µÄ·´Ó¦Îª£ºCO+2H2?CH3OH£®ÒÑÖª£ºH2£¨g£©¡¢CO£¨g£©¡¢CH3OH£¨l£©µÄȼÉÕÈÈ¡÷H·Ö±ðΪ-285.8kJ/mol¡¢-283.0kJ/molºÍ-726.5kJ/mol£®Ôò£ºCH3OH£¨l£©²»ÍêȫȼÉÕÉú³ÉCOºÍҺ̬H2OµÄÈÈ»¯Ñ§·´Ó¦·½³ÌʽΪCH3OH£¨l£©+O2£¨g£©=CO£¨g£©+2H2O£¨l£©£»¡÷H=-443.5kJ/mol£®
£¨3£©ÔÚÒ»¶¨Î¶ȡ¢Ñ¹Ç¿ºÍ´ß»¯Ìõ¼þÏ£¬¹¤ÒµÉÏÓÃH2COºÍCOºÏ³ÉCH3OCH3£º
3H2£¨g£©+3CO£¨g£©?CH3OCH3£¨g£©+CO2£¨g£©¡÷H=-246.4KJ•mol-1
¢ÙÔÚÒ»¶¨Ìõ¼þϵÄÃܱÕÈÝÆ÷ÖУ¬¸Ã·´Ó¦´ïµ½Æ½ºâ£¬Ö»¸Ä±äÒ»¸öÌõ¼þÄÜͬʱÌá¸ß·´Ó¦ËÙÂʺÍCOµÄת»¯ÂʵÄÊÇcd£¨Ìî×ÖĸÐòºÅ£©£®
a£®½µµÍÎÂ¶È b£®¼ÓÈë´ß»¯¼Á c£®ËõСÈÝÆ÷Ìå»ý d£®Ôö¼ÓH2µÄŨ¶È e£®Ôö¼ÓCOµÄŨ¶È
¢ÚÔÚÒ»Ìå»ý¿É±äµÄÃܱÕÈÝÆ÷ÖгäÈë3molH2¡¢3molCO¡¢1molCH3OCH3¡¢1molCO2£¬ÔÚÒ»¶¨Î¶ȺÍѹǿÏ·¢ÉúÉÏÊö·´Ó¦£¬¾Ò»¶¨Ê±¼ä´ïµ½Æ½ºâ£¬²âµÃƽºâʱ»ìºÏÆøÌåµÄÃܶÈÊÇͬÎÂͬѹÏÂÆðʼµÄ1.6±¶£®·´Ó¦¿ªÊ¼Ê±Õý¡¢Äæ·´Ó¦ËÙÂʵĴóС£ºvÕý£¾vÄæ£¨Ìî¡°£¾¡±¡°£¼¡±»ò¡°=¡±£©£¬Æ½ºâʱCOµÄÎïÖʵÄÁ¿·ÖÊýΪ15%£®
£¨4£©Ò»¶¨Ìõ¼þÏ¿ÉÓü״¼ÓëCO·´Ó¦Éú³É´×ËáÏû³ýCOÎÛȾ£¬³£ÎÂÏ£¬½«amol•L-1µÄ´×ËáÓëbmol•L-1µÄBa£¨OH£©2ÈÜÒºµÈÌå»ý»ìºÏ£¬³ä·Ö·´Ó¦ºó£¬ÈÜÒºÖдæÔÚ2c£¨Ba2+£©=c£¨CH3COO-£©£¬Ôò¸Ã»ìºÏÈÜÒºÖд×ËáµÄµçÀë³£ÊýKa=$\frac{2b}{a-2b}$¡Á10-7 mol•L-1£¨Óú¬aºÍbµÄ´úÊýʽ±íʾ£¬Ìå»ý±ä»¯ºöÂÔ²»¼Æ£©£®
£¨2£©ÔÚ¸ßÎÂÏÂÒ»Ñõ»¯Ì¼¿É½«¶þÑõ»¯Áò»¹ÔΪµ¥ÖÊÁò£®
¢ÙC£¨s£©+O2£¨g£©=CO2£¨g£©¡÷H1=-393.5kJ•mol
¢ÚCO2£¨g£©+C£¨s£©=2CO£¨g£©¡÷H2=+172.5kJ•mol
¢ÛS£¨s£©+O2£¨g£©=SO2£¨g£©¡÷H3=-296.0kJ•mol
ÔòCOÓëSO2·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ2CO£¨g£©+SO2£¨g£©=CO2£¨g£©+S£¨s£©¡÷H=-270kJ/mol£®
£¨3£©Áò´úÁòËáÄÆÈÜÒºÓëÏ¡ÁòËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪNa2S2O3+H2SO4¨TNa2SO4+SO2¡ü+S¡ý+H2O£®ÏÂÁи÷×éʵÑéÖÐ×îÏȳöÏÖ»ë×ǵÄÊÇD£¨Ìî×Öĸ´úºÅ£©£®
| ʵÑé | ·´Ó¦Î¶È/¡æ | Na2S2O3ÈÜÒº | Ï¡H2SO4 | H2O | ||
| V/mL | c/£¨mol•L-1£© | V/mL | c/£¨mol•L-1£© | V/mL | ||
| A | 25 | 5 | 0.1 | 10 | 0.1 | 5 |
| B | 25 | 5 | 0.2 | 5 | 0.2 | 10 |
| C | 35 | 5 | 0.1 | 10 | 0.1 | 5 |
| D | 35 | 5 | 0.2 | 5 | 0.2 | 10 |
| A£® | ³ÎÇå͸Ã÷µÄÈÜÒºÖУºNa+¡¢K+¡¢MnO4-¡¢NO3- | |
| B£® | pH=13µÄÈÜÒºÖУºNa+¡¢K+¡¢SO42-¡¢HCO3- | |
| C£® | 0.1 mol•L-1 NaClOÈÜÒºÖУºK+¡¢Na+¡¢NO3-¡¢I- | |
| D£® | 0.1 mol•L-1 FeCl3ÈÜÒºÖУºNa+¡¢NH4+¡¢SCN-¡¢SO42- |