ÌâÄ¿ÄÚÈÝ
13£®µª»¯Ã¾ÊÇ¿ÆÑ§¼ÒÃÇÖÆ±¸µÄÒ»ÖÖÖØÒª»¯ºÏÎËü¿ÉÓɵ¥Ö»Ö±½Ó»¯ºÏ¶ø³É£¬ËüÓëË®×÷ÓõIJúÎï֮һΪNH3£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺£¨1£©Na3NÊÇÓÉÀë×Ó¼üÐγɵÄÀë×Ó»¯ºÏÎд³öËüµÄµç×Óʽ£º
£¨2£©Na3NÓëË®·´Ó¦ÊôÓÚ¸´·Ö½â £¨Ìî»ù±¾·´Ó¦ÀàÐÍ£©£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£ºNa3N+3H2O=NH3¡ü+3NaOH£®
£¨3£©Na+ÓëN3-µÄ°ë¾¶¹ØÏµÊÇNa+£¼£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©N3-£®
£¨4£©Mg3N2ÓëÑÎËáµÄ·´Ó¦Éú³ÉÁ½ÖÖÑΣ¬Óõç×Óʽ±íʾÆäÖÐÖ»º¬ÓÐÀë×Ó¼üµÄÑεÄÐγɹý³Ì
·ÖÎö £¨1£©»îÆÃ½ðÊôÔªËØÓë»îÆÃ·Ç½ðÊôÔªËØÖ®¼äÐγÉÀë×Ó¼ü£»µª»¯ÄÆÊÇÀë×Ó»¯ºÏÎÈý¸öÄÆÔ×ÓʧȥÈý¸öµç×Ó£¬¸øNÔ×Ó£¬Ê¹NÔ×Ó×îÍâ²ã´ïµ½Îȶ¨½á¹¹£¬µç×ÓʽÐèÒª±ê×¢Àë×ÓËù´øµçºÉÊý£»
£¨2£©µª»¯ÄÆÓëË®·´Ó¦Éú³ÉNH3ºÍÒ»ÖÖÇ¿¼î£¬¸ù¾Ý·´Ó¦·½³ÌʽµÄÌØµã£¬Ç¿¼îÖ»ÄÜÊÇNaOH£¬ÊµÖÊÊÇNa+½áºÏË®µçÀë³öµÄOH-£¬N3-½áºÏË®µçÀë³öµÄH+£¬¹ÊÊôÓÚ¸´·Ö½â·´Ó¦£»
£¨3£©ÕâÁ½ÖÖÀë×ӵĺËÍâµç×ÓÅŲ¼Ïàͬ£¬ºËÍâµç×ÓÅŲ¼Ïàͬ£¬Àë×Ó°ë¾¶ËæÔ×ÓÐòÊýµÄÔö´ó¶ø¼õС£»
£¨4£©µª»¯Ã¾ÑÎËá·´Ó¦Éú³ÉÂÈ»¯Ã¾ºÍÂÈ»¯ï§£»MgCl2ÊôÓÚÀë×Ó»¯ºÏÎþÀë×ÓÓëÁ½¸öÂÈÀë×Óͨ¹ýÀë×Ó¼ü½áºÏ£»ÂÈ»¯ï§ÎªÀë×Ó¾§Ì壬Óɰ±¸ùÀë×ÓÓëÂÈÀë×Óͨ¹ýÀë×Ó¼ü½áºÏÔÚÒ»Æð£®
½â´ð ½â£º£¨1£©NÔªËØÓëNaÖ®¼äÐγÉÀë×Ó¼ü£¬µª»¯ÄÆÊÇÀë×Ó»¯ºÏÎÈý¸öÄÆÔ×ÓʧȥÈý¸öµç×Ó£¬¸øNÔ×Ó£¬Ê¹NÔ×Ó×îÍâ²ã´ïµ½Îȶ¨½á¹¹£¬Æäµç×ÓʽΪ£º
£¬
¹Ê´ð°¸Îª£ºÀë×Ó£»Àë×Ó£»
£»
£¨2£©µª»¯ÄÆÓëË®·´Ó¦Éú³ÉNH3ºÍÒ»ÖÖÇ¿¼î£¬¸ù¾Ý·´Ó¦·½³ÌʽµÄÌØµã£¬Ç¿¼îÖ»ÄÜÊÇNaOH£¬Æä·´Ó¦·½³Ìʽ£ºNa3N+3H2O=NH3¡ü+3NaOH£¬ÊµÖÊÊÇNa+½áºÏË®µçÀë³öµÄOH-£¬N3-½áºÏË®µçÀë³öµÄH+£¬¹ÊÊôÓÚ¸´·Ö½â·´Ó¦£¬
¹Ê´ð°¸Îª£º¸´·Ö½â£»Na3N+3H2O=NH3¡ü+3NaOH£»
£¨3£©ÕâÁ½ÖÖÀë×ӵĺËÍâµç×ÓÅŲ¼Ïàͬ£¬ºËÍâµç×ÓÅŲ¼Ïàͬ£¬Àë×Ó°ë¾¶ËæÔ×ÓÐòÊýµÄÔö´ó¶ø¼õС£¬¹Êr£¨Na+£©£¼r£¨N3-£©£¬¹Ê´ð°¸Îª£º£¼£»
£¨4£©µª»¯Ã¾ÑÎËá·´Ó¦Éú³ÉÂÈ»¯Ã¾ºÍÂÈ»¯ï§£¬MgCl2ÊôÓÚÀë×Ó»¯ºÏÎþÀë×ÓÓëÁ½¸öÂÈÀë×Óͨ¹ýÀë×Ó¼ü½áºÏ£¬MgCl2ÊôÓÚÀë×Ó»¯ºÏÎMg×îÍâ²ãÁ½¸öµç×Ó±»Á½¸öClÔ×ӵõ½£¬Óõç×Óʽ±íʾÐγɹý³ÌΪ
£»ÂÈ»¯ï§ÊÇÀë×Ó»¯ºÏÎÓɰ±¸ùÀë×ÓÓëÂÈÀë×Ó¹¹³É£¬µç×ÓʽΪ£º
£»
¹Ê´ð°¸Îª£ºÁ½£»
£»
£®
µãÆÀ ±¾Ì⿼²éµç×Óʽ¡¢»¯Ñ§·´Ó¦·½³Ìʽ¡¢»¯Ñ§¼ü¡¢Àë×Ó°ë¾¶µÄ´óС±È½ÏµÈ֪ʶ£¬Ö÷ÒªÊÇÎïÖÊÐÔÖʵÄÀí½âÓ¦Óã¬ÕÆÎÕ»ù´¡ÊǽâÌâ¹Ø¼ü£¬ÌâÄ¿ÄѶÈÖеȣ¬²àÖØÓÚ¿¼²éѧÉú¶Ô»ù´¡ÖªÊ¶µÄÓ¦ÓÃÄÜÁ¦£®
| ʵÑé ±àºÅ | ʵÑéÄ¿µÄ | ζÈ/¡æ | ´ß»¯¼Á ÖÊÁ¿/g | ·´Ó¦Îï³õʼŨ¶È /10-3mol•L-1 | |
| H2 | I2 | ||||
| ¢ñ | ΪÒÔÏÂʵÑé×÷²ÎÕÕ | 457 | 0 | 7 | 9 |
| ¢ò | ¢Ù | 420 | ¢Ú | 7 | 9 |
| ¢ó | ̽¾¿´ß»¯¼Á¶Ô¸Ã·´Ó¦ËÙÂʵÄÓ°Ïì | ¢Û | 10 | 7 | 9 |
£¨2£©ÊµÑé¢ñÖУ¬I2µÄÎïÖʵÄÁ¿Å¨¶È£¨c£©ËæÊ±¼ä£¨t£©µÄ±ä»¯ÈçͼËùʾ£®
¸ù¾ÝͼÖÐÊý¾Ý»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙÔÚ0¡«5minÄÚ·´Ó¦µÄƽ¾ùËÙÂÊv£¨I2£©=1¡Á10-3mol•L-1•min-1£®
¢Ú¸ÃζÈÏ£¬·´Ó¦µÄƽºâ³£ÊýK=$\frac{{c}^{2}£¨HI£©}{c£¨{H}_{2}£©¡Ác£¨{I}_{2}£©}$=48£®£¨Ç°¿Õд±í´ïʽ£¬ºó¿Õд¼ÆËãËùµÃµÄÊý¾Ý£©
¢Û¸Ãͬѧ»¹ÏëÓô˷´Ó¦Ñо¿Ñ¹Ç¿¶Ô»¯Ñ§Æ½ºâÒÆ¶¯µÄÓ°Ï죬ÇëÎÊÄÜ·ñ´ïµ½ÊµÑéÄ¿µÄ£¿Çë˵Ã÷ÔÒò£®
²»ÄÜ£¨Ìî¡°ÄÜ¡±¡¢²»ÄÜ¡±£©£¬ÔÒòÊǸ÷´Ó¦Ç°ºóÆøÌ弯Á¿ÊýÏàµÈ£¬Æ½ºâ²»ÊÜѹǿµÄÓ°Ï죮
£¨1£©ÅäÖÆ100mL 0.10mol/L NaOH±ê×¼ÈÜÒº£®
£¨2£©È¡20.00mL´ý²âÏ¡ÑÎËáÈÜÒº·ÅÈë×¶ÐÎÆ¿ÖУ¬²¢µÎ¼Ó2¡«3µÎ·Ó̪×÷ָʾ¼Á£¬ÓÃ×Ô¼ºÅäÖÆµÄ±ê×¼NaOHÈÜÒº½øÐе樣®Öظ´ÉÏÊöµÎ¶¨²Ù×÷2¡«3´Î£¬¼Ç¼Êý¾ÝÈçÏ£®
| ʵÑé±àºÅ | NaOHÈÜÒºµÎÈëµÄÌå»ý£¨mL£© | ´ý²âÑÎËáÈÜÒºµÄÌå»ý£¨mL£© |
| 1 | 22.62 | 20.00 |
| 2 | 22.72 | 20.00 |
| 3 | 22.80 | 20.00 |
¢Ú¸ù¾ÝÉÏÊöÊý¾Ý£¬¼ÆËã³ö¸ÃÑÎËáµÄŨ¶ÈԼΪ0.11mol/L£¨±£ÁôÁ½Î»ÓÐЧÊý×Ö£©
¢ÛÏÂÁвÙ×÷£¨ÆäËû²Ù×÷ÕýÈ·£©»áÔì³ÉʵÑé²â¶¨½á¹ûÆ«¸ßµÄÓÐDF£®£¨¶àÑ¡¿Û·Ö£©
A¡¢µÎ¶¨ÖÕµã¶ÁÊýʱ¸©ÊÓ¶ÁÊý
B¡¢ËáʽµÎ¶¨¹ÜʹÓÃǰ£¬Ë®Ï´ºóδÓôý²âÑÎËáÈÜÒºÈóÏ´
C¡¢×¶ÐÎÆ¿Ë®Ï´ºóδ¸ÉÔï
D¡¢³ÆÁ¿Ç°NaOH¹ÌÌåÖлìÓÐNa2CO3¹ÌÌå
E¡¢ÅäÖÆºÃµÄNaOH±ê×¼ÈÜÒº±£´æ²»µ±£¬²¿·ÖÓë¿ÕÆøÖеÄCO2·´Ó¦Éú³ÉÁËNa2CO3
F¡¢¼îʽµÎ¶¨¹Ü¼â×첿·ÖÓÐÆøÅÝ£¬µÎ¶¨ºóÏûʧ
£¨3£©ÊÒÎÂÏ£¬Èô½«0.1mol•L-1ÑÎËáµÎÈë20mL 0.1mol•L-1°±Ë®ÖУ¬ÈÜÒºpHËæ¼ÓÈëÑÎËáÌå»ýµÄ±ä»¯ÇúÏßÈçͼËùʾ£®
¢ÙNH3•H2OµÄµçÀë·½³ÌʽÊÇNH3•H2O?NH4++OH-£®
¢ÚbµãËùʾÈÜÒºÖеÄÈÜÖÊÊÇNH4Cl¡¢NH3?H2O£®
¢ÛcµãËùʾÈÜÒºÖУ¬Àë×ÓŨ¶È´Ó´óµ½Ð¡µÄ¹ØÏµÎªc£¨Cl-£©£¾c£¨NH4+£©£¾c£¨H+£©£¾c£¨OH-£©£¬ÔÚ¸ÃÈÜÒºÖдæÔÚ¶àÖÖÊØºã¹ØÏµ£¬ÆäÖÐc£¨NH4+£©+c£¨H+£©=c£¨Cl-£©+c£¨OH-£©£¨ÓÃÀë×ÓŨ¶È±íʾ£©£®
| A£® | Na¡¢Mg¡¢Al»¹ÔÐÔÒÀ´ÎÔöÇ¿ | |
| B£® | HCl¡¢PH3¡¢H2SÎȶ¨ÐÔÒÀ´Î¼õÈõ | |
| C£® | NaOH¡¢KOH¡¢Ca£¨OH£©2¼îÐÔÒÀ´Î¼õÈõ | |
| D£® | S2-¡¢Cl-¡¢K+¡¢Ca2+Àë×Ó°ë¾¶ÒÀ´Î¼õС |
| A£® | 1 L 1 mol•L-1µÄNaClO ÈÜÒºÖк¬ÓÐClO-µÄÊýĿΪNA | |
| B£® | ³£Î³£Ñ¹Ï£¬4.6gCH3CH2OHÖк¬ÓÐ 6NA¸öC-H¼ü | |
| C£® | ³£Î³£Ñ¹Ï£¬14 g ÓÉN2ÓëCO×é³ÉµÄ»ìºÏÆøÌ庬ÓеÄÔ×ÓÊýĿΪNA | |
| D£® | ±ê×¼×´¿öÏ£¬6.72 L NO2ÓëË®³ä·Ö·´Ó¦×ªÒƵĵç×ÓÊýĿΪ0.1NA |
| A£® | ½«2mol SO3ÆøÌåͨÈëÒ»¶¨ÃܱÕÈÝÆ÷ÖУ¬·´Ó¦´ïµ½Æ½ºâºóÎüÊÕQ kJÈÈÁ¿£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ 2SO3£¨g£©?2SO2£¨g£©+O2£¨g£©¡÷H=+Q kJ•mol-1 | |
| B£® | Ïò0.1mol/L¡¢pH=1µÄNaHAÈÜÒºÖмÓÈëNaOHÈÜÒº£ºH++OH-=H2O | |
| C£® | ÒÔ½ðÊôÒøÎªÑô¼«µç½â±¥ºÍÁòËáÍÈÜÒº£ºCu2++2H2O=2Cu+O2¡ü+4H+ | |
| D£® | NH4Al£¨SO4£©2ÈÜÒºÖмÓÈëBa£¨OH£©2ÈÜҺʹSO42-ÍêÈ«³Áµí£ºAl3++2SO42-+2Ba2++4OH-=AlO2-+2BaSO4¡ý+2H2O |