题目内容

7.已知448℃时反应H2(g)+I2(g)?2HI(g)的平衡常数是49,则HI(g)?$\frac{1}{2}$H2(g)+$\frac{1}{2}$I2(g)在该温度下的平衡常数是(  )
A.$\frac{1}{49}$B.49C.$\frac{1}{7}$D.7

分析 HI(g)?$\frac{1}{2}$H2(g)+$\frac{1}{2}$I2(g)的化学平衡常数=$\frac{[c({H}_{2}).c({I}_{2})]^{\frac{1}{2}}}{c(HI)}$=$\frac{1}{\frac{c(HI)}{[c({H}_{2}).c({I}_{2})]^{\frac{1}{2}}}}$=$\frac{1}{[\frac{c(HI)}{c({H}_{2}).c({I}_{2})}]^{\frac{1}{2}}}$,据此分析解答.

解答 解:448℃时反应H2(g)+I2(g)?2HI(g)的平衡常数是49,该温度下HI(g)?$\frac{1}{2}$H2(g)+$\frac{1}{2}$I2(g)的化学平衡常数=$\frac{[c({H}_{2}).c({I}_{2})]^{\frac{1}{2}}}{c(HI)}$=$\frac{1}{\frac{c(HI)}{[c({H}_{2}).c({I}_{2})]^{\frac{1}{2}}}}$=$\frac{1}{[\frac{c(HI)}{c({H}_{2}).c({I}_{2})}]^{\frac{1}{2}}}$=$\frac{1}{(49)^{\frac{1}{2}}}$=$\frac{1}{7}$,故选C.

点评 本题考查化学平衡常数有关计算,为高频考点,侧重考查学生分析计算能力,明确两个方程式及化学平衡常数关系是解本题关键,题目难度中等.

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