ÌâÄ¿ÄÚÈÝ
16£®³£ÎÂÏ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©| A£® | ÔÚNa2CO3ÈÜÒºÖУºc£¨OH-£©-c£¨H+£©=c£¨HCO3-£©+c£¨H2CO3£© | |
| B£® | 0.2mol•L?1µÄCH3COONaÈÜÒºÓë0.1mol•L?1µÄHClÈÜÒºµÈÌå»ý»ìºÏ£¬ÈÜÒºÏÔËáÐÔ£ºc£¨Na+£©£¾c£¨Cl-£©£¾c£¨CH3COO-£©£¾c£¨H+£©£¾c£¨OH-£© | |
| C£® | pHÏàͬµÄ̼ËáÄÆÈÜÒºÓë̼ËáÇâÄÆÈÜÒº£ºc£¨NaHCO3£©£¾c£¨Na2CO3£© | |
| D£® | 0.1mol•L?1µÄHCN£¨ÈõËᣩºÍ0.1mol•L?1µÄNaCNµÈÌå»ý»ìºÏ£ºc£¨HCN£©+c£¨CN-£©=c£¨Na+£© |
·ÖÎö A£®Èκεç½âÖÊÈÜÒºÖж¼´æÔÚµçºÉÊØºãºÍÎïÁÏÊØºã£¬¸ù¾ÝµçºÉÊØºãºÍÎïÁÏÊØºãÅжϣ»
B.0.2mol•L?1µÄCH3COONaÈÜÒºÓë0.1mol•L?1µÄHClÈÜÒºµÈÌå»ý»ìºÏ£¬ÈÜÒºÖÐÈÜÖÊΪµÈÎïÖʵÄÁ¿Å¨¶ÈµÄCH3COONa¡¢NaCl¡¢CH3COOH£¬´×ËáµçÀë³Ì¶È´óÓÚ´×Ëá¸ùÀë×ÓË®½â³Ì¶Èµ¼ÖÂÈÜÒº³ÊËáÐÔ£¬µ«´×ËáµçÀë³Ì¶ÈºÍ´×Ëá¸ùÀë×ÓË®½â³Ì¶È¶¼½ÏС£»
C£®Ì¼Ëá¸ùÀë×ÓË®½â³Ì¶È´óÓÚ̼ËáÇâ¸ùÀë×ÓË®½â³Ì¶È£¬Ëá¸ùÀë×ÓË®½â³Ì¶ÈÔ½´ó£¬pHÏàͬµÄÄÆÑÎÈÜҺŨ¶ÈԽС£»
D£®Èκεç½âÖÊÈÜÒºÖж¼´æÔÚÎïÁÏÊØºã£¬¸ù¾ÝÎïÁÏÊØºãÅжϣ®
½â´ð ½â£ºA£®Èκεç½âÖÊÈÜÒºÖж¼´æÔÚµçºÉÊØºãºÍÎïÁÏÊØºã£¬¸ù¾ÝµçºÉÊØºãµÃc£¨Na+£©+c£¨H+£©=2¡¡¡¡c£¨CO32-£©+c£¨HCO3-£©+c£¨OH-£©¡¢¸ù¾ÝÎïÁÏÊØºãµÃc£¨Na+£©=2c£¨CO32-£©+2c£¨HCO3-£©+2c£¨H2CO3£©£¬ËùÒÔµÃc£¨OH-£©-c£¨H+£©=c£¨HCO3-£©+2c£¨H2CO3£©£¬¹ÊA´íÎó£»
B.0.2mol•L?1µÄCH3COONaÈÜÒºÓë0.1mol•L?1µÄHClÈÜÒºµÈÌå»ý»ìºÏ£¬ÈÜÒºÖÐÈÜÖÊΪµÈÎïÖʵÄÁ¿Å¨¶ÈµÄCH3COONa¡¢NaCl¡¢CH3COOH£¬´×ËáµçÀë³Ì¶È´óÓÚ´×Ëá¸ùÀë×ÓË®½â³Ì¶È£¬Ôòc£¨Cl-£©£¼c£¨CH3COO-£©£¬µ¼ÖÂÈÜÒº³ÊËáÐÔ£¬ËùÒÔc£¨H+£©£¾c£¨OH-£©£¬µ«´×ËáµçÀë³Ì¶ÈºÍ´×Ëá¸ùÀë×ÓË®½â³Ì¶È¶¼½ÏС£¬ËùÒÔÀë×ÓŨ¶È´óС˳ÐòÊÇc£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨Cl-£©£¾c£¨H+£©£¾c£¨OH-£©£¬¹ÊB´íÎó£»
C£®Ì¼Ëá¸ùÀë×ÓË®½â³Ì¶È´óÓÚ̼ËáÇâ¸ùÀë×ÓË®½â³Ì¶È£¬Ëá¸ùÀë×ÓË®½â³Ì¶ÈÔ½´ó£¬pHÏàͬµÄÄÆÑÎÈÜҺŨ¶ÈԽС£¬ËùÒÔpHÏàͬµÄ̼ËáÄÆÈÜÒºÓë̼ËáÇâÄÆÈÜÒº£ºc£¨NaHCO3£©£¾c£¨Na2CO3£©£¬¹ÊCÕýÈ·£»
D£®Èκεç½âÖÊÈÜÒºÖж¼´æÔÚÎïÁÏÊØºã£¬¸ù¾ÝÎïÁÏÊØºãµÃc£¨HCN£©+c£¨CN-£©=2c£¨Na+£©£¬¹ÊD´íÎó£»
¹ÊÑ¡C£®
µãÆÀ ±¾Ì⿼²éÀë×ÓŨ¶È´óС±È½Ï£¬Îª¸ßƵ¿¼µã£¬Ã÷È·ÈÜÒºÖÐÈÜÖʼ°ÈÜÒºËá¼îÐÔÊǽⱾÌâ¹Ø¼ü£¬Èκεç½âÖÊÈÜÒºÖж¼´æÔÚµçºÉÊØºãºÍÎïÁÏÊØºã£¬Ò×´íÑ¡ÏîÊÇBC£®
| A£® | ´ß»¯¼ÁÔÚÊÊÒ˵Äζȷ¶Î§Ê±µÄ´ß»¯Ð§¹û¸üºÃ | |
| B£® | ʹÓô߻¯¼Á£¬¿ÉÒÔÔö´ó»î»¯·Ö×Ó°Ù·ÖÊý£¬¼Ó¿ì·´Ó¦ËÙÂÊ | |
| C£® | ´ß»¯¼ÁÔÚ»¯Ñ§·´Ó¦Ç°ºóÖÊÁ¿ºÍ»¯Ñ§ÐÔÖʲ»±äÊÇÒòΪ´ß»¯¼Á²»²Î¼Ó»¯Ñ§·´Ó¦ | |
| D£® | пÓëÑÎËᷴӦʱ£¬¼ÓÈ뼸µÎÁòËáÍÈÜÒº¿É¼Ó¿ì·´Ó¦ËÙÂÊ£¬µ«ÁòËáͲ»×÷´ß»¯¼Á |
| A£® | SO2¡úSO32- | B£® | Cl2¡úHCl | C£® | Na+¡úNa | D£® | S¡úSO2 |
| A£® | Q2=$\frac{1}{2{Q}_{1}}$=98.5 | B£® | Q2=$\frac{1}{2{Q}_{1}}$£¼98.5 | C£® | Q2£¼$\frac{1}{2{Q}_{1}}$£¼98.5 | D£® | ÎÞ·¨È·¶¨ |