Question

16£®Ä³Î¶ÈÏ£¬ÏÂÁÐÈÜÒºµÄÀë×ÓŨ¶È¹ØϵʽÕýÈ·µÄÊÇ£¨¡¡¡¡£©

• A£® 0.1 mol/L µÄÁòËáï§ÈÜÒºÖУºc£¨NH₄⁺£©£¾c£¨SO₄²?£©£¾c£¨H⁺£©£¾c£¨OH?£©
• B£® 0.2mol/LNaHCO₃ÈÜÒºÓë0.1mol/LNaOHÈÜÒºµÈÌå»ý»ìºÏ£ºc£¨H⁺£©¨Tc£¨OH?£©+c£¨HCO₃?£©+2c£¨H₂CO₃£©
• C£® pHÖ®ºÍΪ14µÄH₂C₂O₄ÓëKOH ÈÜÒº»ìºÏ£ºc£¨K⁺£©£¾c£¨H⁺£©£¾c£¨OH?£©£¾c£¨HC₂O₄?£©
• D£® pH=5 µÄH₂SÈÜÒºÖУ¬c£¨H⁺£©£¾c£¨HS?£©=1¡Á10^-5mol/L

Answer 1

·ÖÎö A£®ÁòËáï§ÎªÇ¿ËáÈõ¼îÑΣ¬ÈÜÒº³ÊËáÐÔ£¬ÇÒNH₄⁺Ë®½â³Ì¶È½ÏС£»
B.0.2mol/LNaHCO₃ÈÜÒºÓë0.1mol/LNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬µÃµ½NaHCO₃ºÍNa₂CO₃µÄ»ìºÏÈÜÒº£»
C£®pHÖ®ºÍΪ14µÄH₂C₂O₄ÓëKOH ÈÜÒº£¬Á½ÈÜÒºÖеÄc£¨H⁺£©¨Tc£¨OH?£©£¬µ«H₂C₂O₄ΪÈõËᣬH₂C₂O₄¹ýÁ¿£»
D£®H₂SΪ¶þÔªÈõËᣬ´æÔÚÁ½²½µçÀ룮

½â´ð ½â£ºA£®ÁòËáï§ÎªÇ¿ËáÈõ¼îÑΣ¬ÈÜÒº³ÊËáÐÔ£¬ÇÒNH₄⁺Ë®½â³Ì¶È½ÏС£¬ÔòÈÜÒºÖдæÔÚc£¨NH₄⁺£©£¾c£¨SO₄²?£©£¾c£¨H⁺£©£¾c£¨OH?£©£¬¹ÊAÕýÈ·£»
B.0.2mol/LNaHCO₃ÈÜÒºÓë0.1mol/LNaOHÈÜÒºµÈÌå»ý»ìºÏ£¬µÃµ½NaHCO₃ºÍNa₂CO₃µÄ»ìºÏÈÜÒº£¬ÈÜÒº³Ê¼îÐÔ£¬Ôòc£¨HCO₃?£©£¾c£¨H⁺£©£¬¹ÊB´íÎó£»
C£®pHÖ®ºÍΪ14µÄH₂C₂O₄ÓëKOH ÈÜÒº£¬Á½ÈÜÒºÖеÄc£¨H⁺£©¨Tc£¨OH?£©£¬µ«H₂C₂O₄ΪÈõËᣬH₂C₂O₄¹ýÁ¿£¬Ó¦Îªc£¨HC₂O₄?£©£¾c£¨H⁺£©£¾c£¨OH?£©£¬¹ÊC´íÎó£»
D£®H₂SΪ¶þÔªÈõËᣬ´æÔÚÁ½²½µçÀ룬c£¨HS?£©£¼1¡Á10^-5mol/L£¬¹ÊD´íÎó£®
¹ÊÑ¡A£®

µãÆÀ ±¾Ì⿼²éÀë×ÓŨ¶ÈµÄ´óС±È½Ï£¬Îª¸ßƵ¿¼µãºÍ³£¼ûÌâÐÍ£¬ÊǶÔ֪ʶµÄ×ÛºÏÔËÓã¬ÐèҪѧÉú¾ß±¸ÔúʵµÄ»ù´¡ÖªÊ¶ÓëÔËÓÃ֪ʶ·ÖÎöÎÊÌâ¡¢½â¾öÎÊÌâµÄÄÜÁ¦£¬ÌâÄ¿ÄѶȽϴó£¬×¢Òâ°ÑÎÕÈõµç½âÖʵĵçÀë¡¢ÑÎÀàµÄË®½âÒÔ¼°Å¨¶È±È½ÏµÄ½Ç¶È£®