探究下表中的奥秘,并完成填空:
| 一元二次方程 | 两个根 | 二次三项式因式分解 |
| x2-2x+1=0 | x1=1,x2=1 | x2-2x+1=(x-1)(x-1) |
| x2-3x+2=0 | x1=1,x2=2 | x2-3x+2=(x-1)(x-2) |
| 3x2+x-2=0 | ||
| 2x2+5x+2=0 | ||
| 4x2+13x+3=0 | x1=________,x2=________ | 4x2+13x+3=4(x+________)(x+________) |
| 一元二次方程 | 两个根 | 二次三项式因式分解 |
| x2-2x+1=0 | x1=1,x2=1 | x2-2x+1=(x-1)(x-1) |
| x2-3x+2=0 | x1=1,x2=2 | x2-3x+2=(x-1)(x-2) |
| 3x2+x-2=0 | ||
| 2x2+5x+2=0 | ||
| 4x2+13x+3=0 | x1=________,x2=________ | 4x2+13x+3=4(x+________)(x+________) |