题目内容
先化简,再求值:
÷
•
,其中x=
.
| x2-1 |
| x2-2x+1 |
| x+1 |
| x-1 |
| 1-x |
| 1+x |
| 1 |
| 2 |
| x2-1 |
| x2-2x+1 |
| x+1 |
| x-1 |
| 1-x |
| 1+x |
=
| (x+1)(x-1) |
| (x-1)2 |
| x-1 |
| x+1 |
| 1-x |
| 1+x |
=
| 1-x |
| x+1 |
把x=
| 1 |
| 2 |
原式=
1-
| ||
|
| 1 |
| 3 |
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题目内容
| x2-1 |
| x2-2x+1 |
| x+1 |
| x-1 |
| 1-x |
| 1+x |
| 1 |
| 2 |
| x2-1 |
| x2-2x+1 |
| x+1 |
| x-1 |
| 1-x |
| 1+x |
| (x+1)(x-1) |
| (x-1)2 |
| x-1 |
| x+1 |
| 1-x |
| 1+x |
| 1-x |
| x+1 |
| 1 |
| 2 |
1-
| ||
|
| 1 |
| 3 |