题目内容
先化简,再求值
÷
+
,其中x=3.
| 4 |
| x2-16 |
| 2 |
| x-4 |
| x |
| x+4 |
原式=
•
+
=
+
=
;
当x=3时,原式=
.
| 4 |
| (x+4)(x-4) |
| x-4 |
| 2 |
| x |
| x+4 |
=
| 2 |
| x+4 |
| x |
| x+4 |
=
| x+2 |
| x+4 |
当x=3时,原式=
| 5 |
| 7 |
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题目内容
| 4 |
| x2-16 |
| 2 |
| x-4 |
| x |
| x+4 |
| 4 |
| (x+4)(x-4) |
| x-4 |
| 2 |
| x |
| x+4 |
| 2 |
| x+4 |
| x |
| x+4 |
| x+2 |
| x+4 |
| 5 |
| 7 |