题目内容
先化简再求值| 1 |
| 1-x |
| x+1 |
| x2+2x+1 |
| 1 | ||
|
分析:先通分,然后进行分式的加减运算,最后代入x的值计算即可.
解答:解:原式=
+
=
+
=
=
(4分)
当x=
=
时,
原式=
=
=-
.(8分)
| 1 |
| 1-x |
| x+1 |
| (x+1)2 |
=
| 1 |
| 1-x |
| 1 |
| 1+x |
=
| 1+x+1-x |
| 1-x2 |
=
| 2 |
| 1-x2 |
当x=
| 1 | ||
|
| ||
| 2 |
原式=
| 2 |
| 1-x2 |
=
| 2 | ||||
1-(
|
=-
| 4 |
| 3 |
| 3 |
点评:本题考查了二次根式的化简和分式的化简、求值,为了降低计算的难度,杜绝繁琐的计算,本题代数式结构简单,化简后的结果简单,计算简单,把考查重点放在化简的规则和方法上.
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