题目内容
9.解下列方程组:(1)$\left\{\begin{array}{l}{x+y=4}\\{x-y=2}\end{array}\right.$;
(2)$\left\{\begin{array}{l}{2x+y=8}\\{5x-2y=2}\end{array}\right.$.
分析 (1)直接利用加减消元法解方程得出答案;
(2)直接利用加减消元法解方程得出答案.
解答 解:(1)$\left\{\begin{array}{l}{x+y=4①}\\{x-y=2②}\end{array}\right.$,
①+②得:
2x=6,
解得:x=3,
则y=1,
故方程组的解为:$\left\{\begin{array}{l}{x=3}\\{y=1}\end{array}\right.$;
(2)$\left\{\begin{array}{l}{2x+y=8①}\\{5x-2y=2②}\end{array}\right.$,
①×2+②得:
9x=18,
解得:x=2,
则y=4,
故方程组的解为:$\left\{\begin{array}{l}{x=2}\\{y=4}\end{array}\right.$.
点评 此题主要考查了二元一次方程组的解法,正确掌握解题方法是解题关键.
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