题目内容
化简求值:3(xy-y2)-[-xy+2(y2+xy)]+2,其中x=-
,y=-1.
| 1 |
| 2 |
3(xy-y2)-[-xy+2(y2+xy)]+2,
=3xy-3y2+xy-2y2-2xy+2,
=2xy-5y2+2,
当x=-
,y=-1时,原式=2×(-
)×(-1)-5×1+2,
=1-5+2,
=-2.
=3xy-3y2+xy-2y2-2xy+2,
=2xy-5y2+2,
当x=-
| 1 |
| 2 |
| 1 |
| 2 |
=1-5+2,
=-2.
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