题目内容
计算:
(1)
-
;
(2)
÷(
-
).
(1)
| x2 |
| y-x |
| y2 |
| y-x |
(2)
| 1 |
| x-y |
| 1 |
| y |
| 1 |
| x |
考点:分式的混合运算
专题:
分析:(1)利用同分母的分式加减运算法则直接化简求出即可;
(2)利用分式运算法则化简求出即可.
(2)利用分式运算法则化简求出即可.
解答:解:(1)
-
=
=
=-x-y;
(2)
÷(
-
)
=
÷
=
.
| x2 |
| y-x |
| y2 |
| y-x |
=
| x2-y2 |
| y-x |
=
| (x-y)(x+y) |
| -(x-y) |
=-x-y;
(2)
| 1 |
| x-y |
| 1 |
| y |
| 1 |
| x |
=
| 1 |
| x-y |
| x-y |
| xy |
=
| xy |
| (x-y)2 |
点评:此题主要考查了分式的混合运算,正确化简分式是解题关键.
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