题目内容
先化简,再求值:| x2+2x |
| 1+x |
| 2 |
| x+1 |
分析:先化简,再把x=2代入计算即可.
解答:解:原式=
÷(x-
)
=
÷
=
×
=
当x=2时,原式=
=
=2.
| x2+2x |
| 1+x |
| 2 |
| x+1 |
=
| x(x+2) |
| x+1 |
| x2+x-2 |
| x+1 |
=
| x(x+2) |
| x+1 |
| x+1 |
| (x+2)(x-1) |
=
| x |
| x-1 |
当x=2时,原式=
| x |
| x-1 |
| 2 |
| 2-1 |
点评:本题考查了二次根式的化简求值,解题的关键是化简.
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