Question

18．方程组$\left\{\begin{array}{l}{2a-3b=15}\\{3a+5b=32.9}\end{array}\right.$的解为$\left\{\begin{array}{l}{a=9.3}\\{b=3.2}\end{array}\right.$，则方程组$\left\{\begin{array}{l}{2（x+2）-3（y-1）=13}\\{3（x+2）+5（y-1）=30.9}\end{array}\right.$的解是$\left\{\begin{array}{l}{x=7.3}\\{y=4.2}\end{array}\right.$．

Answer 1

分析 仿照已知方程组的解确定出所求方程组的解即可．

解答 解：方程组$\left\{\begin{array}{l}{2a-3b=15}\\{3a+5b=32.9}\end{array}\right.$的解为$\left\{\begin{array}{l}{a=9.3}\\{b=3.2}\end{array}\right.$，
则方程组$\left\{\begin{array}{l}{2（x+2）-3（y-1）=13}\\{3（x+2）+5（y-1）=30.9}\end{array}\right.$的解为$\left\{\begin{array}{l}{x+2=9.3}\\{y-1=3.2}\end{array}\right.$，即$\left\{\begin{array}{l}{x=7.3}\\{y=4.2}\end{array}\right.$．
故答案为：$\left\{\begin{array}{l}{x=7.3}\\{y=4.2}\end{array}\right.$．

点评 此题考查了二元一次方程组的解，熟练掌握运算法则是解本题的关键．