题目内容
已知:| 1 |
| x |
| 1 |
| y |
| x-2xy-y |
| x+2xy-y |
分析:把
-
=3变形为x-y=-3xy,把
变为
,代入后进行约分即可.
| 1 |
| x |
| 1 |
| y |
| x-2xy-y |
| x+2xy-y |
| (x-y)-2xy |
| (x-y)+2xy |
解答:解:
-
=3,
y-x=3xy,
∴x-y=-3xy,
∴
=
=
=
=5.
故答案为:5.
| 1 |
| x |
| 1 |
| y |
y-x=3xy,
∴x-y=-3xy,
∴
| x-2xy-y |
| x+2xy-y |
=
| (x-y)-2xy |
| (x-y)+2xy |
=
| -3xy-2xy |
| -3xy+2xy |
=
| -5xy |
| -xy |
=5.
故答案为:5.
点评:本题主要考查对分式的加减,约分,分式的基本性质等知识点的理解和掌握,能整体代入是解此题的关键.
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