题目内容
先化简,再求值:(
-
)÷
,其中x=-3.
| x+2 |
| x2-2x |
| x-1 |
| x2-4x+4 |
| 4-x |
| x |
考点:分式的化简求值
专题:
分析:先根据分式混合运算的法则把原式进行化简,再把x=-3代入进行计算即可.
解答:解:原式=[
-
]•
=
•
=
•
=
•
=-
,
当x=-3时,原式=-
=-
.
| x+2 |
| x(x-2) |
| x-1 |
| (x-2)2 |
| x |
| 4-x |
=
| (x+2)(x-2)-x(x-1) |
| x(x-2)2 |
| x |
| 4-x |
=
| x2-4-x2+x |
| x(x-2)2 |
| x |
| 4-x |
=
| x-4 |
| x(x-2)2 |
| x |
| 4-x |
=-
| 1 |
| (x-2)2 |
当x=-3时,原式=-
| 1 |
| (-3-2)2 |
| 1 |
| 25 |
点评:本题考查的是分式的化简求值,熟知分式混合运算的法则是解答此题的关键.
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