题目内容
化简
÷(x-1)•
| x2-1 |
| x2+4x+4 |
| x+2 |
| x+1 |
原式=
•
•
=
．
故答案为
．
| (x+1)(x-1) |
| (x+2)2 |
| 1 |
| x-1 |
| x+2 |
| x+1 |
| 1 |
| x+2 |
故答案为
| 1 |
| x+2 |
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题目内容
| x2-1 |
| x2+4x+4 |
| x+2 |
| x+1 |
| (x+1)(x-1) |
| (x+2)2 |
| 1 |
| x-1 |
| x+2 |
| x+1 |
| 1 |
| x+2 |
| 1 |
| x+2 |