题目内容
| a |
| (a-b)(a-c) |
| b |
| (b-c)(b-a) |
| c |
| (c-a)(c-b) |
分析:先通分,再把分子相加减即可.
解答:解:原式=
-
+
=
=
=
=0.
故选D.
| a |
| (a-b)(a-c) |
| b |
| (a-b)(b-c) |
| c |
| (a-c)(b-c) |
=
| a(b-c)-b(a-c)+c(a-b) |
| (a-b)(b-c)(a-c) |
=
| ab-ac-ab+bc+ac-bc |
| (a-b)(b-c)(a-c) |
=
| 0 |
| (a-b)(b-c)(a-c) |
=0.
故选D.
点评:本题考查的是分式的加减法,熟知异分母分式的加减就转化为同分母分式的加减是解答此题的关键.
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