题目内容
已知x=2007，y=2008，求
÷
+
的值．
| x2+2xy+y2 |
| 5x2-4xy |
| x+y |
| 5x-4y |
| x2-y |
| x |
原式=
•
+
=
+
=
=x+1．
当x=2007时，原式=2007+1=2008．
| (x+y)2 |
| x(5x-4y) |
| 5x-4y |
| x+y |
| x2-y |
| x |
=
| x+y |
| x |
| x2-y |
| x |
=
| x2+x |
| x |
=x+1．
当x=2007时，原式=2007+1=2008．
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