题目内容
先化简再求值:| 1 |
| x-1 |
| x2+4x+3 |
| x-1 |
| 3 |
分析:本题要先把分式化简,再将x的值代入求解.
解答:解:原式=
-
•
=
-
=-
;
当x=2+
时,
原式=-
=-
=-4+2
.
| 1 |
| x-1 |
| (x+1)(x+3) |
| x-1 |
| 1 |
| (x+1)(x-1) |
=
| x-1 |
| (x-1)2 |
| x+3 |
| (x-1)2 |
=-
| 4 |
| (x-1)2 |
当x=2+
| 3 |
原式=-
| 4 | ||
(2+
|
| 4 | ||
4+2
|
| 3 |
点评:本题是分式的混合运算,特别要注意运算顺序以及符号的处理.
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