题目内容
化简求值:
(1)(x2+3x)(x-3)-x(x-2)2+(-x-y)(y-x)其中x=3,y=-2.
(2)已知x=
,y=
,求代数式(2x+3y)2-(2x-3y)2的值.
(1)(x2+3x)(x-3)-x(x-2)2+(-x-y)(y-x)其中x=3,y=-2.
(2)已知x=
| 1 |
| 6 |
| 1 |
| 8 |
(1)原式=x3-3x2+3x2-9x-x(x2-4x+4)+x2-y2
=5x23x-y2,
当x=3,y=-2时,原式=5×9-13×3-4=2;
(2)(2x+3y)2-(2x-3y)2
=(2x+3y+2x-3y)(2x+3y-2x+3y),
=24xy
∴当x=
,y=
时,原式=24×
×
=
.
=5x23x-y2,
当x=3,y=-2时,原式=5×9-13×3-4=2;
(2)(2x+3y)2-(2x-3y)2
=(2x+3y+2x-3y)(2x+3y-2x+3y),
=24xy
∴当x=
| 1 |
| 6 |
| 1 |
| 8 |
| 1 |
| 6 |
| 1 |
| 8 |
| 1 |
| 2 |
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