题目内容
计算:
(1)-4-(+2)+1-2-(-3);
(2)3
+(-2
)+5
+(-8
);
(3)(-
)÷(-
)×(-
);
(4)
÷(-2
)-
×
-
;
(5)-22+3×(-1)4-(-4)×5;
(6)(-3)2-(-5)3×(
)2-16÷|-2|
(1)-4-(+2)+1-2-(-3);
(2)3
| 1 |
| 4 |
| 3 |
| 5 |
| 3 |
| 4 |
| 2 |
| 5 |
(3)(-
| 1 |
| 2 |
| 3 |
| 8 |
| 1 |
| 8 |
(4)
| 5 |
| 7 |
| 2 |
| 5 |
| 5 |
| 7 |
| 5 |
| 12 |
| 5 |
| 3 |
(5)-22+3×(-1)4-(-4)×5;
(6)(-3)2-(-5)3×(
| 2 |
| 5 |
考点:有理数的混合运算
专题:计算题
分析:(1)先化简,再计算即可求解;
(2)先算同分母分数,再相加即可求解;
(3)将除法变为乘法,再约分计算;
(4)先算乘除法,再算加减法;
(5)(6)按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的.
(2)先算同分母分数,再相加即可求解;
(3)将除法变为乘法,再约分计算;
(4)先算乘除法,再算加减法;
(5)(6)按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的.
解答:解:(1)-4-(+2)+1-2-(-3)
=-4-2+1-2+3
=-8+4
=-4;
(2)3
+(-2
)+5
+(-8
)
=(3
+5
)+(-2
-8
)
=9-11
=-2;
(3)(-
)÷(-
)×(-
)
=-
×
×
=-
;
(4)
÷(-2
)-
×
-
=-
×
-
×
-
=-
×(
+
)-
=-
×
-
=-
-
=-
;
(5)-22+3×(-1)4-(-4)×5
=-4+3×1+20
=-4+3+20
=-4+23
=19;
(6)(-3)2-(-5)3×(
)2-16÷|-2|
=9+125×
-16÷2
=9+20-8
=21.
=-4-2+1-2+3
=-8+4
=-4;
(2)3
| 1 |
| 4 |
| 3 |
| 5 |
| 3 |
| 4 |
| 2 |
| 5 |
=(3
| 1 |
| 4 |
| 3 |
| 4 |
| 3 |
| 5 |
| 2 |
| 5 |
=9-11
=-2;
(3)(-
| 1 |
| 2 |
| 3 |
| 8 |
| 1 |
| 8 |
=-
| 1 |
| 2 |
| 8 |
| 3 |
| 1 |
| 8 |
=-
| 1 |
| 6 |
(4)
| 5 |
| 7 |
| 2 |
| 5 |
| 5 |
| 7 |
| 5 |
| 12 |
| 5 |
| 3 |
=-
| 5 |
| 7 |
| 5 |
| 12 |
| 5 |
| 7 |
| 5 |
| 12 |
| 5 |
| 3 |
=-
| 5 |
| 7 |
| 5 |
| 12 |
| 5 |
| 12 |
| 5 |
| 3 |
=-
| 5 |
| 7 |
| 5 |
| 6 |
| 5 |
| 3 |
=-
| 25 |
| 42 |
| 70 |
| 42 |
=-
| 95 |
| 42 |
(5)-22+3×(-1)4-(-4)×5
=-4+3×1+20
=-4+3+20
=-4+23
=19;
(6)(-3)2-(-5)3×(
| 2 |
| 5 |
=9+125×
| 4 |
| 25 |
=9+20-8
=21.
点评:本题考查的是有理数的运算能力.注意:
(1)要正确掌握运算顺序,在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序;
(2)去括号法则:--得+,-+得-,++得+,+-得-.
(1)要正确掌握运算顺序,在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序;
(2)去括号法则:--得+,-+得-,++得+,+-得-.
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