题目内容
化简：
-
-1，并指出x的取值范围．
| x |
| x-1 |
| 3 |
| (x-1)(x+2) |
原式=
-
-
=
=
=
；
x的取值范围是x≠-2且x≠1的实数．
| x(x+2) |
| (x-1)(x+2) |
| 3 |
| (x-1)(x+2) |
| (x-1)(x+2) |
| (x-1)(x+2) |
=
| x2+2x-3-x2-x+2 |
| (x-1)(x+2) |
=
| x-1 |
| (x-1)(x+2) |
=
| 1 |
| x+2 |
x的取值范围是x≠-2且x≠1的实数．
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