题目内容
对于有理数a、b,定义a⊙b=3a+2b,则[(x+y)⊙(x-y)]⊙3x化简后得
- A.0
- B.6x
- C.21x+3y
- D.9x+6y
C
[(x+y)⊙(x-y)]⊙3x=[3(x+y)+2(x-y)]⊙3x=(5x+y)⊙3x=3(5x+y)+2(3x)=21x+3y
[(x+y)⊙(x-y)]⊙3x=[3(x+y)+2(x-y)]⊙3x=(5x+y)⊙3x=3(5x+y)+2(3x)=21x+3y
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