题目内容
先化简,再求值:| x2-1 |
| x2-2x+1 |
| x2-2x |
| x2-3x+2 |
| 1 | ||
|
分析:首先把除法运算转化成乘法运算,然后进行加减运算,最后再代入求值.
解答:原式=
-
×
=
-
=
,
当x=
=
+1时,
原式=
=1+
.
| (x+1)(x-1) |
| (x-1)2 |
| x(x-2) |
| (x-1)(x-2) |
| 1 |
| x |
=
| x+1 |
| x-1 |
| 1 |
| x-1 |
=
| x |
| x-1 |
当x=
| 1 | ||
|
| 2 |
原式=
| ||
|
| ||
| 2 |
点评:本题的关键是化简,然后把给定的值代入求值.
练习册系列答案
相关题目