题目内容
(1)
÷
;
(2)
+6a
;
(3)|3-
|+8cos230°-4tan60°.
| 12 |
| 24 |
(2)
| 1 |
| 2 |
| 4a3 |
|
(3)|3-
| 12 |
(1)原式=
=
=
;
(2)原式=a
+2a
=3a
;
(3)原式=|3-2
|+8×(
)2-4×
=2
-3+6-4
=3-2
.
| 12÷24 |
|
| ||
| 2 |
(2)原式=a
| a |
| a |
| a |
(3)原式=|3-2
| 3 |
| ||
| 2 |
| 3 |
| 3 |
| 3 |
| 3 |
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