题目内容
(1)计算:
|
| 24 |
| 2 |
| 3 |
| 8 |
(2)先化简,再求值:(a-
| 3 |
| 3 |
| 5 |
| 1 |
| 2 |
分析:(1)根据
×
=
=
=2
,|
-
|=
-
,
=2
进行解答.
(2)首先多项式乘以多项式(单项式)进行展开,然后合并同类项,最后代值计算.
|
| 24 |
|
| 12 |
| 3 |
| 2 |
| 3 |
| 3 |
| 2 |
| 8 |
| 2 |
(2)首先多项式乘以多项式(单项式)进行展开,然后合并同类项,最后代值计算.
解答:解:(1)
×
+|
-
|-
,
=
+
-
-2
,
=2
+
-
-2
,
=3
-3
;
(2)(a-
)(a+
)-a(a-6),
=a2-3-a2+6a,
=6a-3,
当a=
+
时,原式=6
+3-3=6
.
|
| 24 |
| 2 |
| 3 |
| 8 |
=
|
| 3 |
| 2 |
| 2 |
=2
| 3 |
| 3 |
| 2 |
| 2 |
=3
| 3 |
| 2 |
(2)(a-
| 3 |
| 3 |
=a2-3-a2+6a,
=6a-3,
当a=
| 5 |
| 1 |
| 2 |
| 5 |
| 5 |
点评:本题主要考查二次根式的化简求值的知识点,对(1)题要熟练掌握二次根式的性质,对(2)必须化到最简再代值计算,本题基础题,比较简单.
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