题目内容
计算:
(1)
+
(2)
-
÷
.
(1)
| a |
| a-b |
| b |
| b-a |
(2)
| 1 |
| x+2 |
| x2+2x+1 |
| x+2 |
| x2-1 |
| x-1 |
(1)原式=
-
=
=1;
(2)原式=
-
•
=
-
=-
.
| a |
| a-b |
| b |
| a-b |
=
| a-b |
| a-b |
=1;
(2)原式=
| 1 |
| x+2 |
| (x+1)2 |
| x+2 |
| 1 |
| x+1 |
=
| 1 |
| x+2 |
| x+1 |
| x+2 |
=-
| x |
| x+2 |
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