题目内容
化简求值题:(1)先化简,再求值:
| 4 |
| x2-16 |
| 2 |
| x-4 |
| x |
| x+4 |
(2)先化简,再求值:
| y-3 |
| 4y-8 |
| 5 |
| y-2 |
(3)先化简,再求值:(1-
| 1 |
| x+2 |
| x2-1 |
| x+2 |
(4)先化简,再求值:
| x+3 |
| x2-9 |
| 3 |
| x-3 |
分析:(1)先算除法,再算同分母加法,然后将x=3代入即可求得分式的值;
(2)首先把括号里因式进行通分,然后把除法运算转化成乘法运算,进行约分化简,再把数代入,不能选2,±3,会使原式无意义.
(3)先将括号内的部分通分,再将除法转化为乘法,然后将x=2代入即可求得分式的值;
(4)先约分化简,再计算同分母加法,然后将x=-1代入即可求得分式的值.
(2)首先把括号里因式进行通分,然后把除法运算转化成乘法运算,进行约分化简,再把数代入,不能选2,±3,会使原式无意义.
(3)先将括号内的部分通分,再将除法转化为乘法,然后将x=2代入即可求得分式的值;
(4)先约分化简,再计算同分母加法,然后将x=-1代入即可求得分式的值.
解答:解:(1)
÷
+
=
•
+
=
,
把x=3代入,原式=
.
(2)
÷(y+2-
)
=
•
=
,
把x=1代入,原式=
.
(3)(1-
)÷
=
•
=
,
把x=2代入,原式=1.
(4)
+
=
+
=
,
把x=-1代入,原式=-1.
| 4 |
| x2-16 |
| 2 |
| x-4 |
| x |
| x+4 |
=
| 4 |
| (x+4)(x-4) |
| x-4 |
| 2 |
| x |
| x+4 |
=
| x+2 |
| x+4 |
把x=3代入,原式=
| 5 |
| 7 |
(2)
| y-3 |
| 4y-8 |
| 5 |
| y-2 |
=
| y-3 |
| 4(y-2) |
| y-2 |
| y2-4-5 |
=
| 1 |
| 4(y+3) |
把x=1代入,原式=
| 1 |
| 16 |
(3)(1-
| 1 |
| x+2 |
| x2-1 |
| x+2 |
=
| x+2-1 |
| x+2 |
| x+2 |
| (x+1)(x-1) |
=
| 1 |
| x-1 |
把x=2代入,原式=1.
(4)
| x+3 |
| x2-9 |
| 3 |
| x-3 |
=
| 1 |
| x-3 |
| 3 |
| x-3 |
=
| 4 |
| x-3 |
把x=-1代入,原式=-1.
点评:考查分式的化简与求值,主要的知识点是因式分解、通分、约分等.注意(2)化简后,代入的数不能使分母的值为0.
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