题目内容
(1)计算(
+
)(
-2);
(2)
•(-
)÷
(a>0,b>0)
| 3 |
| 2 |
| 6 |
(2)
| 8a3b2 |
| 3 |
| 2 |
| 2a2b |
| 9ab |
(1)原式=
×
-2
+
×
-2
=3
-2
+2
-2
=
;
(2)原式=2ab
•(-
a
)÷3
=2ab•(-
a)•
=-2a2b.
| 3 |
| 6 |
| 3 |
| 2 |
| 6 |
| 2 |
| 2 |
| 3 |
| 3 |
| 2 |
| 2 |
(2)原式=2ab
| 2a |
| 3 |
| 2 |
| 2b |
| ab |
| 3 |
| 2 |
| 1 |
| 3 |
|
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