题目内容
计算或化简:
(1)(
-1)2-(
-
)(
+
);
(2)
•
-3a2
-
÷
+
.
(1)(
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
(2)
| 3a2 |
| 9a |
|
| 4a4 |
|
| a3 |
(1)原式=4-2
-(-1)=5-2
;
(2)原式=a
•3
-3a2•
-2a2•
+a
=3a
-3a
-2a
+a
=a
-2a
.
| 3 |
| 3 |
(2)原式=a
| 3 |
| a |
| ||
| a |
| ||
| a |
| a |
=3a
| 3a |
| a |
| 3a |
| a |
=a
| 3a |
| a |
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