题目内容
化简:(1+
)÷
.
| 1 |
| x-2 |
| x2-2x+1 |
| x2-4 |
分析:首先计算括号内的式子,然后对第二个分式的分子分母分解因式,转化成乘法运算,最后进行约分解求解.
解答:解:原式=
÷
=
÷
=
•
=
.
| x-1 |
| x-2 |
| x2-2x+1 |
| x2-4 |
=
| x-1 |
| x-2 |
| (x-1)2 |
| (x+2)(x-2) |
=
| x-1 |
| x-2 |
| (x+2)(x-2) |
| (x-1)2 |
=
| x+2 |
| x-1 |
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.
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