题目内容
化简求值:| 2x-2 |
| x2-1 |
| 1 |
| x+1 |
分析:先把括号内通分,然后把各分式的分子和分母因式分解得到原式=
•
,再约分,然后把x=2代入计算即可.
| 2(x-1) |
| (x+1)(x-1) |
| x+1 |
| x |
解答:解:原式=
÷
=
•
=
,
当x=2,原式=
=1.
| 2(x-1) |
| (x+1)(x-1) |
| x |
| x+1 |
=
| 2(x-1) |
| (x+1)(x-1) |
| x+1 |
| x |
=
| 2 |
| x |
当x=2,原式=
| 2 |
| 2 |
点评:本题考查了分式的化简求值:先把各分式的分子或分母因式分解,然后进行通分或约分,得到最简分式或整式,再把满足条件的字母的值代入计算得到对应的分式的值.
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