题目内容
计算题
(1)(-12)-5+(-14)-(-39)
(2)
×(-7)÷(-
)×7
(3)-
×[(-
)2-2]
(4)-14÷(-5)2×(-
)+|0.8-1|
(5)(
-
+
+
)×(-48)
(6)(-26)÷(
-
-1)×6.
(1)(-12)-5+(-14)-(-39)
(2)
| 1 |
| 7 |
| 1 |
| 7 |
(3)-
| 3 |
| 2 |
| 2 |
| 3 |
(4)-14÷(-5)2×(-
| 5 |
| 3 |
(5)(
| 11 |
| 12 |
| 7 |
| 6 |
| 3 |
| 4 |
| 13 |
| 24 |
(6)(-26)÷(
| 1 |
| 3 |
| 1 |
| 2 |
考点:有理数的混合运算
专题:
分析:(1)先化简,再计算即可求解;
(2)变形为[
÷(-
)]×(-7×7),再计算即可求解;
(3)(4)按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的;
(5)直接运用乘法的分配律计算;
(6)先算小括号里面的减法,再算括号外面的乘除法.
(2)变形为[
| 1 |
| 7 |
| 1 |
| 7 |
(3)(4)按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的;
(5)直接运用乘法的分配律计算;
(6)先算小括号里面的减法,再算括号外面的乘除法.
解答:解:(1)(-12)-5+(-14)-(-39)
=-12-3-14+39
=-29+39
=10;
(2)
×(-7)÷(-
)×7
=[
÷(-
)]×(-7×7)
=-1×(-49)
=49;
(3)-
×[(-
)2-2]
=-
×[
-2]
=-
×[-
]
=2
;
(4)-14÷(-5)2×(-
)+|0.8-1|
=-1÷25×(-
)+0.2
=
+
=
;
(5)(
-
+
+
)×(-48)
=-44+42-36-26
=-106+42
=-64;
(6)(-26)÷(
-
-1)×6
=(-26)÷(-
)×6
=
.
=-12-3-14+39
=-29+39
=10;
(2)
| 1 |
| 7 |
| 1 |
| 7 |
=[
| 1 |
| 7 |
| 1 |
| 7 |
=-1×(-49)
=49;
(3)-
| 3 |
| 2 |
| 2 |
| 3 |
=-
| 3 |
| 2 |
| 4 |
| 9 |
=-
| 3 |
| 2 |
| 14 |
| 9 |
=2
| 1 |
| 3 |
(4)-14÷(-5)2×(-
| 5 |
| 3 |
=-1÷25×(-
| 5 |
| 3 |
=
| 1 |
| 15 |
| 3 |
| 15 |
=
| 4 |
| 15 |
(5)(
| 11 |
| 12 |
| 7 |
| 6 |
| 3 |
| 4 |
| 13 |
| 24 |
=-44+42-36-26
=-106+42
=-64;
(6)(-26)÷(
| 1 |
| 3 |
| 1 |
| 2 |
=(-26)÷(-
| 7 |
| 6 |
=
| 936 |
| 7 |
点评:本题考查的是有理数的运算能力.注意:
(1)要正确掌握运算顺序,在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序;
(2)去括号法则:--得+,-+得-,++得+,+-得-.
(1)要正确掌握运算顺序,在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序;
(2)去括号法则:--得+,-+得-,++得+,+-得-.
练习册系列答案
相关题目
反比例函数y=
图象上三个点的坐标分别是A(-2,y1),B(-1,y2),C(2,y3),则y1,y2,y3的大小关系的是( )
| k2+2 |
| x |
| A、y1<y2<y3 |
| B、y3<y2<y1 |
| C、y3<y1<y2 |
| D、y2<y1<y3 |