ÌâÄ¿ÄÚÈÝ

9£®Ä³ÐËȤС×éÓÃÈÜÖÊÖÊÁ¿·ÖÊýΪ 19.6%µÄÏ¡ÁòËáÀ´´¦Àí 10.22 ¿Ëº¬ÓÐ̼ËáÄÆºÍÇâÑõ»¯ÄƵĻìºÏ·ÏÒº£®ËûÃÇÏò·ÏÒºÖмÓÈëÏ¡ÁòËáʱ£¬ËùµÃÈÜÒº pH Óë¼Ó ÈëµÄÏ¡ÁòËáÖÊÁ¿µÄ¹ØÏµÇúÏßÈçͼËùʾ£®µ±·ÏÒºÖеÄÈÜÖÊÇ¡ºÃ·´Ó¦Íêȫʱ£¬ÈÜÒº×ÜÖÊÁ¿Îª20 ¿Ë£®

£¨1£©µ±·´Ó¦½øÐÐÖÁͼÖÐ P µãʱ£¬ÈÜÒºÖеÄÈÜÖÊÓÐNa2SO4£®£¨Ìîд»¯Ñ§Ê½£©
£¨2£©Õû¸ö¹ý³Ì¹²Éú³ÉµÄ¶þÑõ»¯Ì¼ÖÊÁ¿Îª0.22g¿Ë£®
£¨3£©Í¨¹ý¼ÆËãÈ·¶¨Í¼ÖÐmµÄÖµ£®

·ÖÎö £¨1£©¸ù¾ÝͼÏó·ÖÎöÔÚPʱ£¬ÈÜÒºµÄpHµÈÓÚ7£¬ÈÜÒº³ÊÖÐÐÔ£¬·ÏҺǡºÃ´¦ÀíÍꣻ
£¨2£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂɼÆËã¶þÑõ»¯Ì¼µÄÖÊÁ¿£»
£¨3£©¸ù¾Ý¶þÑõ»¯Ì¼µÄÖÊÁ¿ÒÔ¼°Ì¼ËáÄÆÁòËá·´Ó¦µÄ·½³Ìʽ£¬¼ÆËãÓë̼ËáÄÆ·´Ó¦µÄÁòËáµÄÖÊÁ¿£¬½øÒ»²½¼ÆËãmµÄÖµ£®

½â´ð ½â£º£¨1£©ÓÉÓÚÉú³ÉµÄÁòËáÄÆÈÜÒºÏÔÖÐÐÔ£¬ÓÉͼʾ¿ÉÖª£¬µ±·´Ó¦½øÐÐÖÁͼÖÐPµãʱ£¬pH=7£¬È»ºóÓÖϽµ£¬ËµÃ÷´ËʱǡºÃ½«·ÏÒº´¦ÀíÍꣻÇâÑõ»¯ÄÆÓëÁòËá·´Ó¦Éú³ÉÁòËáÄÆºÍË®£¬Ì¼ËáÄÆºÍÁòËáÉú³ÉÁòËáÄÆ¡¢Ë®ºÍ¶þÑõ»¯Ì¼£¬ËùÒÔÈÜÒºÖеÄÈÜÖÊÓÐNa2SO4£»¹ÊÌNa2SO4£»
£¨2£©Éú³ÉµÄ¶þÑõ»¯Ì¼ÖÊÁ¿Îª10.22g+10g-20g=0.22g£®¹ÊÌ0.22£»
£¨3£©ÉèÓë̼ËáÄÆ·´Ó¦µÄÁòËáµÄÖÊÁ¿Îªx
Na2CO3+H2SO4=Na2SO4+H2O+CO2¡ü
                98                             44
                x                             0.22g
$\frac{98}{x}=\frac{44}{0.22g}$
x=0.98g
ÁòËáÈÜÒºµÄÖÊÁ¿Îª$\frac{0.98g}{19.6%}$=5g
ËùÒÔÓëÇâÑõ»¯ÄÆ·´Ó¦µÄÏ¡ÁòËáµÄÖÊÁ¿Îª10g-5g=5g£¬ËùÒÔm=5£®
¹ÊÌ5£®

µãÆÀ ÔÚ½â´ËÀàÌâʱ£¬Ê×ÏÈ·ÖÎö·´Ó¦Ó¦ÓõÄÔ­Àí£¬È»ºó½áºÏͼÏóÖеÄתÕ۵㣬ÒÔ¼°·½³ÌʽÖеıÈÀý¹ØÏµ½øÐнâ´ð£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø