ÌâÄ¿ÄÚÈÝ

3£®»¯Ñ§ÓëÉú»îÃÜÇÐÏà¹Ø£®
£¨1£©Í¼1ΪijʳƷ°ü×°´üµÄ²¿·Ö˵Ã÷£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢ÙÔÚ±ý¸ÉµÄÅäÁÏÖУ¬¸»º¬ÓÍÖ¬µÄÊǾ«Á¶Ö²ÎïÓÍ£»
¢Ú¸ÃÅäÁÏÖи»º¬µ°°×ÖʵÄÎïÖÊÊÇÏʼ¦µ°£»
¢ÛСÂó·ÛÖи»º¬ÌÇÀ࣬ÌÇÀàÔÚÈËÌåÄÚ¾­¹ýһϵÁеı仯×îÖÕת»¯ÎªË®ºÍCO2£¨Ìѧʽ£©£»
¢Ü´ÓÓªÑø¾ùºâµÄ½Ç¶È¿´£¬¸ÃʳƷÖгýË®Í⣬»¹È±ÉÙµÄÓªÑøËØÊÇάÉúËØ£®
£¨2£©Í¼2ÊÇ´ò»ð»úµÄʾÒâͼ£®Çë¸ù¾ÝÓйØÐŠϢ»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ù¹¹³É´ò»ð»úµÄ²ÄÁÏÖÐÊôÓںϳɲÄÁϵÄÊÇc£¨Ìî±êºÅ£©£®
¢ÚÆäȼÁϵÄÖ÷Òª³É·Ö¶¡Í飨C4H10£©ÊôÓÚÓлú£¨Ìî¡°Óлú¡±»ò¡°ÎÞ»ú¡±£©»¯ºÏÎï
¢Û´ò»ð»úµ²·çÕÖͨ·ç¿×µÄ×÷ÓÃÊÇʹ¿ÕÆøÁ÷ͨ£¬ËµÃ÷¸ÃȼÁÏȼÉÕ±ØÐëÓëÑõÆø½Ó´¥£®Èôͨ·ç¿×Í¨Æø²»Á¼£¬¿ÉÄÜÔì³É´ò»ð»úÎÞ·¨Æð»ð»òȼÁϲ»ÍêȫȼÉÕ¶øÉú³ÉÓж¾ÆøÌåCO£¨Ìѧʽ£©£®

·ÖÎö £¨1£©¢Ù¸ù¾ÝʳƷÖи»º¬µÄÓªÑøËØ½øÐнâ´ð£»
¢Ú¸ù¾ÝʳƷÖи»º¬µÄÓªÑøËØÒÔ¼°ÈËÌ屨ÐèµÄÁù´óÓªÑøËØÀ´·ÖÎö£»
¢Û¸ù¾ÝСÂ󸻺¬µí·Û£¬ÌÇÀàÔÚÈËÌåÄÚ¾­¹ýһϵÁеı仯×îÖÕת»¯ÎªË®ºÍ¶þÑõ»¯Ì¼½øÐзÖÎö£»
¢Ü¸ù¾ÝʳƷÖи»º¬µÄÓªÑøËØÒÔ¼°ÈËÌ屨ÐèµÄÁù´óÓªÑøËØÀ´·ÖÎö£»
£¨2£©¢Ù¸ù¾Ý²ÄÁϵķÖÀà½øÐзÖÎö£»
¢Ú¸ù¾ÝÓлú»¯ºÏÎïµÄ¸ÅÄî½øÐзÖÎö£»
¢Û¸ù¾ÝȼÉÕÐèҪͬʱÂú×ãÈý¸öÌõ¼þ£º¢Ù¿ÉȼÎï¡¢¢ÚÑõÆø»ò¿ÕÆø¡¢¢ÛζÈÒª´ïµ½×Å»ðµã£¬º¬Ì¼ÔªËصÄȼÁÏȼÉÕ²»³ä·Ö»áÉú³ÉÒ»Ñõ»¯Ì¼£¬½øÐзÖÎö½â´ð£®

½â´ð ½â£º£¨1£©¢ÙÔÚ±ý¸ÉµÄÅäÁÏÖУ¬¸»º¬ÓÍÖ¬µÄÊǾ«Á¶Ö²ÎïÓÍ£»
¹ÊÌ¾«Á¶Ö²ÎïÓÍ£»
¢Ú¸ÃÅäÁÏÖи»º¬µ°°×ÖʵÄÎïÖÊÊÇÏʼ¦µ°£»
¹ÊÌÏʼ¦µ°£»
¢ÛСÂó·ÛÖк¬ÓеÄÌÇÀàÎïÖÊÖ÷ÒªÊǵí·Û£¬ÌÇÀàÔÚÈËÌåÄÚ¾­¹ýһϵÁеı仯×îÖÕת»¯ÎªË®ºÍ¶þÑõ»¯Ì¼£»
¹ÊÌCO2£»
¢ÜÈËÌåÐèÒªµÄÁù´óÓªÑøÎïÖÊ£ºµ°°×ÖÊ¡¢ÌÇÀà¡¢ÓÍÖ¬¡¢Î¬ÉúËØ¡¢ÎÞ»úÑκÍË®£¬´ÓÓªÑø¾ùºâµÄ½Ç¶È¿´£¬¸ÃʳƷÖгýË®Í⣬»¹È±ÉÙµÄÓªÑøËØÊÇάÉúËØ£»
¹ÊÌάÉúËØ£»
£¨2£©¢ÙËÜÁÏÊôÓںϳɲÄÁÏ£»
¢Ú¶¡Í麬ÓÐÌ¼ÔªËØ£¬ÊôÓÚÓлú»¯ºÏÎ
¢Û´ò»ð»úµ²·çÕÖͨ·ç¿×µÄ×÷ÓÃÊÇʹ¿ÕÆøÁ÷ͨ£¬ËµÃ÷ȼÁÏȼÉÕÐèÒªÓëÑõÆø½Ó´¥£»º¬Ì¼ÔªËصÄȼÁÏȼÉÕ²»³ä·Ö»áÉú³ÉÒ»Ñõ»¯Ì¼£¬Èôͨ·ç¿×Í¨Æø²»Á¼£¬¿ÉÄÜÔì³É´ò»ð»úÎÞ·¨Æð»ð»òȼÁϲ»ÍêȫȼÉÕ¶øÉú³ÉÓж¾µÄÒ»Ñõ»¯Ì¼£¬¼ÈÀË·ÑÁËȼÁÏÓÖÎÛȾÁË»·¾³£»
¹ÊÌ¢Ùc£»¢ÚÓлú£»¢ÛÑõÆø£»CO£®

µãÆÀ ±¾Ì⿼²éµÄÊÇ»¯Ñ§ÓëÉú»îµÄ֪ʶ£¬Íê³É´ËÌ⣬¿ÉÒÔÒÀ¾ÝÒÑÓеÄ֪ʶ½øÐУ®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
11£®Ä³ÐËȤС×éͬѧÀûÓÃͼ1×°ÖÃÖÆÈ¡ÆøÌ岢̽¾¿ÆøÌåµÄijЩÐÔÖÊ£®
£¨1£©ÖÆÈ¡ÆøÌå
¢ÙÈôÑ¡ÔñAÓëC×éºÏÖÆÈ¡ÑõÆø£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2KClO3$\frac{\underline{MnO_2}}{¡÷}$2KCl+3O2¡ü£®
¢ÚÓÃʯ»ÒʯºÍÏ¡ÑÎËáÖÆÈ¡CO2µÄ»¯Ñ§·½³ÌʽΪCaCO3+2HCl=CaCl2+H2O+CO2¡ü£¬Ñ¡Óõķ¢ÉúÓëÊÕ¼¯×°ÖÃÊÇBE£¨Ìî±êºÅ£©£®Á¬½ÓºÃ×°Ö㬽«Ò©Æ·¼ÓÈë×°ÖÃǰӦ½øÐеIJÙ×÷ÊǼì²é×°ÖÃµÄÆøÃÜÐÔ£®
£¨2£©Ì½¾¿ÆøÌåµÄÐÔÖÊ
ijͬѧÔÚ¿ÕÆøÖеãȼþÌõ£¬ÏëÀûÓÃCO2À´Ï¨ÃðȼÉÕµÄþÌõ£¬½á¹û·¢ÏÖþÌõÔÚ³äÂúCO2µÄ¼¯ÆøÆ¿ÖÐûÓÐϨÃð·´¶ø¾çÁÒȼÉÕ£¬¼¯ÆøÆ¿ÄÚ±Ú³öÏÖºÚÉ«¹ÌÌ壬ƿµ×³öÏÖ°×É«¹ÌÌ壬ʵÑé¹ý³ÌÈçͼ2Ëùʾ£®Çë»Ø´ð£º
¢Ù¼Ð³ÖþÌõµÄÒÇÆ÷Ãû³ÆÊÇÛáÛöǯ£»
¢ÚÉú³ÉµÄºÚÉ«¹ÌÌåÊÇC£¨Ð´»¯Ñ§Ê½£©£»
¢Û²éÔÄ×ÊÁÏ£ºMgO¡¢Mg£¨OH£©2¡¢MgCO3¾ùΪÄÑÈÜÓÚË®µÄ°×É«¹ÌÌ壮ͬѧÌÖÂÛºóÈÏΪ°×É«¹ÌÌå²»¿ÉÄÜÊÇMg£¨OH£©2£¬ÀíÓÉÊÇ·´Ó¦ÎïÖÐûÓÐÇâÔªËØ£®
¢ÜΪ½øÒ»²½È·¶¨°×É«¹ÌÌåµÄ³É·Ö£¬½øÐÐÈçÏÂʵÑ飺
ʵÑé²Ù×÷ʵÑéÏÖÏóʵÑé½áÂÛ
È¡°×É«¹ÌÌåÓÚÊÔ¹ÜÖУ¬¼ÓÈë×ãÁ¿Ï¡ÑÎËá°×É«¹ÌÌåÖð½¥Ïûʧ£¬Ã»ÓÐÆøÅÝð³ö°×É«¹ÌÌå²»ÊÇMgCO3£¬¶øÊÇMgO
¢ÝþÔÚCO2ÖÐȼÉյĻ¯Ñ§·½³ÌʽΪ2Mg+CO2$\frac{\underline{\;µãȼ\;}}{\;}$2MgO+C£»Í¨¹ýÉÏÊö̽¾¿£¬Äã¶ÔȼÉÕ»òÃð»ðµÄÐÂÈÏʶÊÇȼÉÕ²»Ò»¶¨ÓÐÑõÆø²Î¼Ó£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø