ÌâÄ¿ÄÚÈÝ

12£®ÔÚ»¯Ñ§±ä»¯ÖУ¬²Î¼Ó»¯Ñ§·´Ó¦µÄÎïÖÊ×ÜÖÊÁ¿ÓëÉú³ÉÎïµÄ×ÜÖÊÁ¿ÏàµÈ£¬ÇÒ»¯Ñ§·´Ó¦Öи÷·´Ó¦ÎïÓëÉú³ÉÎïÖ®¼äµÄÖÊÁ¿±ÈÊÇÒ»¶¨µÄ£®ÎåÖл¯Ñ§Ð¡×éÓüÓÈÈÂÈËá¼ØÓë¶þÑõ»¯ÃÌÖÆÈ¡ÑõÆø£¬ÊµÑé²âµÃÏà¹ØÊý¾ÝÈçͼËùʾ£º

£¨1£©Ê£ÓàµÄ»ìºÏÎïÖжþÑõ»¯Ã̵ÄÖÊÁ¿Îª1.0g£¬·´Ó¦Éú³ÉÑõÆøµÄÖÊÁ¿Îª19.2g£»
£¨2£©ÈôÒ»¸öÑõÔ­×ÓµÄÖÊÁ¿·Ö±ðΪa Kg£¬Ò»¸ö̼ԭ×ÓµÄÖÊÁ¿Îªw KgÊÔÇóÑõÔ­×ÓµÄÏà¶ÔÔ­×ÓµÄÖÊÁ¿$\frac{12a}{w}$£®

·ÖÎö £¨1£©¸ù¾Ý´ß»¯¼ÁµÄÌØµã¡¢ÖÊÁ¿Êغ㶨ÂɽøÐзÖÎö½â´ð£»
£¨2£©¸ù¾ÝÏà¶ÔÔ­×ÓÖÊÁ¿µÄ¼ÆË㹫ʽ·ÖÎö¼ÆËã

½â´ð ½â£º£¨1£©ÓÉ´ß»¯¼ÁµÄÌØµã¿ÉÖª£¬´ß»¯¼ÁµÄÖÊÁ¿ÔÚ·´Ó¦Ç°ºó²»±ä£¬Ê£ÓàµÄ»ìºÏÎïÖжþÑõ»¯Ã̵ÄÖÊÁ¿Îª1.0 ¿Ë£»¼ÓÈÈÂÈËá¼ØÓë¶þÑõ»¯ÃÌ»ìºÏÎÉú³ÉÁËÑõÆø£¬ÖÁÖÊÁ¿²»ÔÙ¼õÉÙʱ£¬ÓÉÖÊÁ¿Êغ㶨ÂÉ¿ÉÖªÉú³ÉÑõÆøµÄÖÊÁ¿Îª£º49.0g+1.0g-30.8g=19.2g£»
£¨2£©¸ù¾Ý¹«Ê½£ºÄ³Ô­×ÓµÄÏà¶ÔÔ­×ÓÖÊÁ¿=$\frac{Ò»¸ö¸ÃÔ­×ÓµÄÖÊÁ¿}{Ò»¸ö̼ԭ×ÓÖÊÁ¿¡Á\frac{1}{12}}$£¬¿ÉµÃ£ºÑõÔ­×ÓµÄÏà¶ÔÔ­×ÓÖÊÁ¿=$\frac{aKg}{wKg¡Á\frac{1}{12}}$=$\frac{12a}{w}$£»
¹Ê´ðΪ£º£¨1£©1.0£¬19.2£»£¨2£©$\frac{12a}{w}$£®

µãÆÀ Ö÷Òª¿¼²éÁ˸ù¾Ý´ß»¯¼ÁµÄ¸ÅÄî¼°ÖÊÁ¿Êغ㶨ÂɵÄÓ¦Óã¬ÅàÑøÑ§ÉúµÄÓ¦ÓÃ֪ʶµÄÄÜÁ¦ºÍ½â¾öÎÊÌâµÄÄÜÁ¦£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø