题目内容
如图,正四棱柱
中,
,则异面直线
与
所成角的余弦值为( )
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所成角的余弦值为( )
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D
分析:迁连接D′C、AC有,A′B∥D′C,再由异面直线所成角的定义?∠AD′C为异面直线A′B与AD′所成的角,放△AD′C中求解.
解答:解:如图(2),连接D′C、AC,则A′B∥D′C,
∴异面直线A′B与AD′所成的角等于∠AD′C、
令AB=a,∴AA′=2AB=2A、
∴AD′=D′C=
a,AC=
a.
△AD′C中,AD′=D′C=
a,AC=
a.
∴cos∠AD′C=
故答案为
.
点评:本题主要考查异面直线所成角的作法及求法,若在直角三形中可由三角函数定义求解,若在一般三角形中则用余弦定理求解.
解答:解:如图(2),连接D′C、AC,则A′B∥D′C,
∴异面直线A′B与AD′所成的角等于∠AD′C、
令AB=a,∴AA′=2AB=2A、
∴AD′=D′C=
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△AD′C中,AD′=D′C=
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∴cos∠AD′C=
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故答案为
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点评:本题主要考查异面直线所成角的作法及求法,若在直角三形中可由三角函数定义求解,若在一般三角形中则用余弦定理求解.
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