题目内容
9.计算:(x-1)5+5(x-1)4+10(x-1)3+10(x-1)2+5(x-1)分析 由条件利用二项式定理求得所给式子的值.
解答 解:(x-1)5+5(x-1)4+10(x-1)3+10(x-1)2+5(x-1)=(x-1)5+5(x-1)4+10(x-1)3+10(x-1)2+5(x-1)+1-1
=[(x-1)+1]5-1=x5-1.
点评 本题主要考查二项式定理的应用,属于基础题.
练习册系列答案
相关题目
题目内容
9.计算:(x-1)5+5(x-1)4+10(x-1)3+10(x-1)2+5(x-1)分析 由条件利用二项式定理求得所给式子的值.
解答 解:(x-1)5+5(x-1)4+10(x-1)3+10(x-1)2+5(x-1)=(x-1)5+5(x-1)4+10(x-1)3+10(x-1)2+5(x-1)+1-1
=[(x-1)+1]5-1=x5-1.
点评 本题主要考查二项式定理的应用,属于基础题.