题目内容
(12分) 已知圆
过两点
,且圆心
在
上.
(1)求圆
的方程;
(2)设
是直线
上的动点,
是圆
的两条切线,
为切点,求四边形
面积的最小值.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507760386.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507776695.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507760386.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507854593.png)
(1)求圆
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507760386.png)
(2)设
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507901290.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507916726.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507932511.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507760386.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507979429.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507994563.png)
(1)
(2) 2![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508135322.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508103804.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508135322.png)
试题分析:(1)设圆
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001507760386.png)
根据题意,得
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240015081661916.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240015081818609.png)
又|AM|=|BM|=2,|PA|=|PB|, 所以S=2|PA|, ﹍﹍﹍﹍﹍﹍﹍8分
而|PA|=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508213783.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508228686.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508228686.png)
因此要求S的最小值,只需求|PM|的最小值即可,
即在直线3x+4y+8=0上找一点P,使得|PM|的值最小,﹍﹍﹍﹍﹍﹍﹍9分
所以|PM|min=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508259878.png)
所以四边形PAMB面积的最小值为S=2
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508228686.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508291486.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824001508135322.png)
点评:待定系数法求圆的方程,求面积最小转化为利用图形求切线长最小
![](http://thumb.zyjl.cn/images/loading.gif)
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