题目内容
【题目】已知△ABC的面积为8,cosA= ,D为BC上一点,
=
+
,过点D做AB,AC的垂线,垂足分别为E,F,则
= .
【答案】﹣
【解析】解:如图所示,
△ABC中,cosA= ,∴sinA=
=
;
∴S△ABC= |
||
|sinA=
|
||
|
=8,
即| ||
|=20;
设 =λ
,λ∈(0,1),
则 =
+
=
+λ(
﹣
)=(1﹣λ)
+λ
,
又 =
+
,∴λ=
;
∴ =
=
=
=3,
∴S△ABD= |
||
|=
×8=6,
∴| ||
|=12;
又S△ACD= |
||
|=2,
∴| ||
|=4;
∴| ||
||
||
|=48,
∴| ||
|=
=
,
∴
=|
||
|cos(180°﹣A)=
×(﹣
)=﹣
.
所以答案是:﹣ .

练习册系列答案
相关题目