题目内容
【题目】已知△ABC的面积为8,cosA= ,D为BC上一点, = + ,过点D做AB,AC的垂线,垂足分别为E,F,则 = .
【答案】﹣
【解析】解:如图所示,
△ABC中,cosA= ,∴sinA= = ;
∴S△ABC= | || |sinA= | || | =8,
即| || |=20;
设 =λ ,λ∈(0,1),
则 = + = +λ( ﹣ )=(1﹣λ) +λ ,
又 = + ,∴λ= ;
∴ = = = =3,
∴S△ABD= | || |= ×8=6,
∴| || |=12;
又S△ACD= | || |=2,
∴| || |=4;
∴| || || || |=48,
∴| || |= = ,
∴ =| || |cos(180°﹣A)= ×(﹣ )=﹣ .
所以答案是:﹣ .
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