题目内容
给定抛物线
,
是抛物线
的焦点,过点
的直线
与
相交于
、
两点,
为坐标原点.
(1)设
的斜率为1,求以
为直径的圆的方程;
(2)设
,求直线
的方程.
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(1)设
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(2)设
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(1)
(2)
.
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(1)解:
又
直线
的斜率为1,
直线
的方程为:
,代入
,得:
,由根与系数的关系得:
,易得
中点即圆心的坐标为
,又
,
所求的圆的方程为:
.^
(2)
而
,
,
直线
的斜率存在,设直线
的斜率为
,则直线
的方程为:
,代入
,得:
,由根与系数的关系得:
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,
或
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,
直线
的方程为:
.
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(2)
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