题目内容

10.已知矩阵A=$[\begin{array}{l}{1}&{1}\\{1}&{2}\end{array}]$,且AB=$[\begin{array}{l}{1}&{0}\\{0}&{1}\end{array}]$,则矩阵B=$[\begin{array}{l}{2}&{-1}\\{-1}&{1}\end{array}]$.

分析 利用初等变换法计算即得结论.

解答 解:∵A=$[\begin{array}{l}{1}&{1}\\{1}&{2}\end{array}]$,
∴$[\begin{array}{l}{1}&{1}&{1}&{0}\\{1}&{2}&{0}&{1}\end{array}]$→$[\begin{array}{l}{1}&{1}&{1}&{0}\\{0}&{1}&{-1}&{1}\end{array}]$→$[\begin{array}{l}{1}&{0}&{2}&{-1}\\{0}&{1}&{-1}&{1}\end{array}]$,
∴A-1=$[\begin{array}{l}{2}&{-1}\\{-1}&{1}\end{array}]$,
∵AB=$[\begin{array}{l}{1}&{0}\\{0}&{1}\end{array}]$,
∴B=A-1=$[\begin{array}{l}{2}&{-1}\\{-1}&{1}\end{array}]$,
故答案为:$[\begin{array}{l}{2}&{-1}\\{-1}&{1}\end{array}]$.

点评 本题考查矩阵与逆矩阵,注意解题方法的积累,属于基础题.

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