题目内容
(本小题12分)已知c>0,设p:函数
在R上单调递减;q:不等式
>1的解集为R,如果“p或q”为真,且“p且q”为假,求c的取值范围。
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1)由AB=2,AD=
,∠BAD=30?,及余弦定理得
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BD2=AB2+AD2-2AB·ADcos∠BAD=1,
∵AD2+BD2=AB2,∴AD⊥BD.
∵SD⊥平面ABCD,AD
平面ABCD,
∴AD⊥SD,
∴AD⊥平面SBD,又SB
平面SBD,
∴AD⊥SB.
(2)取CD的中点G,连结EG,则EG⊥面BCD,且EG=1.
连AC交BD于F,连FG,则FG//BC且FG=
,又BC⊥BD,∴FG⊥BD
∴
即为所求二面角的平面角
在Rt
中,
∴
。
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BD2=AB2+AD2-2AB·ADcos∠BAD=1,
∵AD2+BD2=AB2,∴AD⊥BD.
∵SD⊥平面ABCD,AD

∴AD⊥SD,
∴AD⊥平面SBD,又SB

∴AD⊥SB.
(2)取CD的中点G,连结EG,则EG⊥面BCD,且EG=1.
连AC交BD于F,连FG,则FG//BC且FG=

∴
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在Rt
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
∴
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略
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