ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ£¨ £©
A.0.1molL-1NaOHÈÜÒºÓë0.2molL-1CH3COOHÈÜÒºµÈÌå»ý»ìºÏºó£ºc(CH3COOH)+c(CH3COO-)=0.1molL-1
B.³£ÎÂÏ£¬½«CH3COONaºÍHClÁ½ÈÜÒº»ìºÏ³ÊÖÐÐÔµÄÈÜÒºÖУºc(Na+)>c(Cl-)=c(CH3COOH)
C.pHÏàµÈµÄ¢ÙNH4Cl¡¢¢Ú(NH4)2SO4¡¢¢ÛNH4HSO4ÈÜÒº£¬c(NH4+)´óС˳ÐòΪ¢Ù=¢Ú>¢Û
D.25¡æʱ£¬pH=aµÄÑÎËáÓëpH=bµÄBa(OH)2ÈÜÒºµÈÌå»ý»ìºÏºó£¬Ç¡ºÃÍêÈ«·´Ó¦£¬Ôòa+b=13
¡¾´ð°¸¡¿D
¡¾½âÎö¡¿
A.¸ù¾ÝÎïÁÏÊغã·ÖÎö£»B.¸ù¾ÝµçºÉÊغã½øÐзÖÎö£»C.¸ù¾ÝÓ°ÏìË®µÄµçÀëÒòËؽøÐзÖÎö£»D.¸ù¾ÝµÈÌå»ýËá¼îÖкͺóÈÜҺŨ¶ÈµÄ¼ÆËã½øÐнâ´ð¡£
A£®µÄNaOHÈÜÒºÓëµÄ´×ËáÈÜÒºµÈÌå»ý»ìºÏºó£¬ËùµÃ»ìºÏÈÜÒºÖеÄÈÜÖÊÊǵĺ͵ģ¬¸ù¾ÝÎïÁÏÊغã¿ÉÖª£º£¬¹ÊAÕýÈ·£»
B£®ÓÉÓÚ»ìºÏºó³ÊÖÐÐÔ£¬¹Ê¼ÓÈëµÄHClµÄÁ¿Ô¶Ð¡ÓÚµÄÁ¿£¬¹Ê£»ËùµÃÈÜÒºÖеÄÈÜÖÊÓУº¡¢ºÍNaCl£¬¸ù¾ÝµçºÉÊغãÓУº £¬ÓÉÓÚÈÜÒº³ÊÖÐÐÔ£¬¹ÊÓУº£¬´Ó¶ø¿ÉÖª£ºc(Na+)=c(CH3COO-)+c(Cl-)¢Ù£»
¶ø¸ù¾ÝÈÜÒºÖÐËùÓеġ¢ºÍ¾ùÀ´×ÔÓÚ¿ÉÖª£ºc(Na+)=c(CH3COO-)+c(CH3COOH)¢Ú£¬½áºÏ¿ÉÖª£¬¹ÊBÕýÈ·£»
C£®Ó붼ÊÇÇ¿ËáÈõ¼îÑΣ¬ÈÜÒºÏÔËáÐÔµÄÔÒòÊÇNH4+Ë®½â£¬Á½ÈÜÒºpHÏàͬ£¬ËµÃ÷¶þÕßÈÜÒºÖÐŨ¶ÈÏàµÈ£¬ÓÉÓÚµçÀëʱ²úÉúʹÈÜÒº³ÊËáÐÔ£¬µÄË®½â±»ÒÖÖÆ£¬Òò´ËÖеÄŨ¶ÈСÓÚ£¬´óС˳ÐòΪ£¬¹ÊCÕýÈ·£»
D£®µÄÑÎËáÖÐÇâÀë×ÓŨ¶ÈΪ£¬µÄÇâÑõ»¯±µÈÜÒºÖÐÇâÑõ¸ùÀë×ÓŨ¶ÈΪ£º£¬Á½ÈÜÒºµÈÌå»ý»ìºÏºóÇ¡ºÃÍêÈ«·´Ó¦£¬ÔòÇâÀë×ÓºÍÇâÑõ¸ùµÄÎïÖʵÄÁ¿µÄÒ»¶¨ÏàµÈ£¬¼´£º£¬Ôò£¬¹ÊD´íÎó£»
´ð°¸£ºD¡£
¡¾ÌâÄ¿¡¿Î¶ÈΪTʱ£¬ÔÚÈý¸öÈÝ»ý¾ùΪ1LµÄºãÈÝÃܱÕÈÝÆ÷Öнö·¢Éú·´Ó¦£º2SO2(g)£«O2(g)2SO3(g) ¦¤H£¼0£¬´ïµ½Æ½ºâʱ£¬ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ
ÈÝÆ÷ ±àºÅ | ÈÝÆ÷ÀàÐÍ | ÆðʼÎïÖʵÄÁ¿ / mol | ƽºâʱSO3µÄÎïÖʵÄÁ¿ / mol | ||
SO2 | O2 | SO3 | |||
I | ºãκãÈÝ | 2 | 1 | 0 | 1.8 |
II | ºãκãѹ | 2 | 1 | 0 | a |
III | ¾øÈȺãÈÝ | 0 | 0 | 2 | b |
A. ÈÝÆ÷IÖÐSO2µÄת»¯ÂÊСÓÚÈÝÆ÷IIÖÐSO2µÄת»¯ÂÊ
B. ÈÝÆ÷IIµÄƽºâ³£Êý´óÓÚÈÝÆ÷IIIÖеÄƽºâ³£Êý
C. ƽºâʱSO3µÄÎïÖʵÄÁ¿£ºa£¾1.8¡¢b£¾1.8
D. ÈôÆðʼʱÏòÈÝÆ÷IÖгäÈë0.10 mol SO2(g)¡¢0.20mol O2(g)ºÍ2.0 mol SO3(g)£¬Ôò´ËʱvÕý£¼vÄæ