ÌâÄ¿ÄÚÈÝ

15£®A¡¢B¡¢C¡¢DËÄÖÖÓлúÎï·Ö×ÓÖеÄ̼ԭ×ÓÊýÄ¿Ïàͬ£®±ê×¼×´¿öÏÂÌþA¶ÔH2µÄÏà¶ÔÃܶÈÊÇ13£¬ÌþB¸úHBr·´Ó¦Éú³ÉC£¬CÓëD»ìºÏºó¼ÓÈëNaOH²¢¼ÓÈÈ£¬¿ÉÉú³ÉB£®
£¨1£©Ð´³öÓлúÎïÖʵĽṹ¼òʽ£ºA£®HC¡ÔCH£»D£®CH3CH2OH
£¨2£©Ð´³öÓйط´Ó¦µÄ»¯Ñ§·½³ÌʽB+HBr£ºCH2=CH2+HBr$\stackrel{Ò»¶¨Ìõ¼þÏÂ}{¡ú}$CH2BrCH3
£¨3£©C ×ª»¯ÎªBµÄ»¯Ñ§·½³ÌʽCH2BrCH3+NaOH$¡ú_{¡÷}^{ÒÒ´¼}$CH2=CH2¡ü+NaBr+H2O
£¨4£©¼ø±ðCÖÐËùº¬¹ÙÄÜÍŵķ½·¨ÊÇÓÃÊÔ¹ÜÁ¿È¡ÉÙÁ¿äåÒÒÍéÈÜÒº£¬È»ºóÏòÈÜÒºÖмÓÈëÇâÑõ»¯ÄƵÄË®ÈÜÒº½øÐмÓÈÈ£¬ÔÙÏòÈÜÒºÖмÓÈëÏõËáËữµÄÏõËáÒøÈÜÒº£¬¹Û²ìÊÇ·ñÓе­»ÆÉ«³ÁµíÉú³É£®

·ÖÎö ±ê×¼×´¿öÏÂÌþA¶ÔH2µÄÏà¶ÔÃܶÈÊÇ13£¬AµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª26£¬ÔòAΪHC¡ÔCH£¬A¡¢B¡¢C¡¢DËÄÖÖÓлúÎï·Ö×ÓÖеÄ̼ԭ×ÓÊýÄ¿Ïàͬ£¬ÌþB¸úHBr·´Ó¦Éú³ÉC£¬ÔòÌþBÖк¬Óв»±¥ºÍ¼ü£¬ÇÒ̼ԭ×Ó¸öÊýΪ2£¬ËùÒÔΪCH2=CH2£¬CΪCH2BrCH3£¬äåÒÒÍéºÍNaOHµÄ´¼ÈÜÒº·¢ÉúÏûÈ¥·´Ó¦Éú³ÉÒÒÏ©£¬ÇÒDÖк¬ÓÐÁ½¸ö̼ԭ×Ó£¬ÔòDΪCH3CH2OH£¬¾Ý´Ë·ÖÎö½â´ð£®

½â´ð ½â£º±ê×¼×´¿öÏÂÌþA¶ÔH2µÄÏà¶ÔÃܶÈÊÇ13£¬AµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª26£¬ÔòAΪHC¡ÔCH£¬A¡¢B¡¢C¡¢DËÄÖÖÓлúÎï·Ö×ÓÖеÄ̼ԭ×ÓÊýÄ¿Ïàͬ£¬ÌþB¸úHBr·´Ó¦Éú³ÉC£¬ÔòÌþBÖк¬Óв»±¥ºÍ¼ü£¬ÇÒ̼ԭ×Ó¸öÊýΪ2£¬ËùÒÔΪ CH2=CH2£¬CΪCH2BrCH3£¬äåÒÒÍéºÍNaOHµÄ´¼ÈÜÒº·¢ÉúÏûÈ¥·´Ó¦Éú³ÉÒÒÏ©£¬ÇÒDÖк¬ÓÐÁ½¸ö̼ԭ×Ó£¬ÔòDΪCH3CH2OH£¬
£¨1£©Í¨¹ýÒÔÉÏ·ÖÎöÖª£¬ÓлúÎïÖÊA¡¢DµÄ½á¹¹¼òʽ·Ö±ðΪHC¡ÔCH¡¢CH3CH2OH£¬¹Ê´ð°¸Îª£ºHC¡ÔCH£»CH3CH2OH£»
£¨2£©ÒÒÏ©ºÍHBrÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦Éú³ÉäåÒÒÍ飬ËùÒÔÒÒÏ©ºÍHBrµÄ·´Ó¦·½³ÌʽΪ£ºCH2=CH2+HBr$\stackrel{Ò»¶¨Ìõ¼þÏÂ}{¡ú}$CH2BrCH3£¬¹Ê´ð°¸Îª£ºCH2=CH2+HBr$\stackrel{Ò»¶¨Ìõ¼þÏÂ}{¡ú}$CH2BrCH3£»
£¨3£©CÊÇäåÒÒÍé¡¢BÊÇÒÒÏ©£¬äåÒÒÍéºÍNaOHµÄ´¼ÈÜÒº¼ÓÈÈ·¢ÉúÏûÈ¥·´Ó¦Éú³ÉÒÒÏ©£¬Cת»¯ÎªBµÄ»¯Ñ§·½³ÌʽCH2BrCH3+NaOH$¡ú_{¡÷}^{ÒÒ´¼}$CH2=CH2¡ü+NaBr+H2O£¬
¹Ê´ð°¸Îª£ºCH2BrCH3+NaOH$¡ú_{¡÷}^{ÒÒ´¼}$CH2=CH2¡ü+NaBr+H2O£»
£¨4£©CÊÇäåÒÒÍ飬Ҫ¼ø¶¨äåÒÒÍéÖÐäåÔªËØ£¬Ó¦¸ÃÓÃÊÔ¹ÜÁ¿È¡ÉÙÁ¿äåÒÒÍéÈÜÒº£¬È»ºóÏòÈÜÒºÖмÓÈëÇâÑõ»¯ÄƵÄË®ÈÜÒº½øÐмÓÈÈ£¬ÔÙÏòÈÜÒºÖмÓÈëÏõËáËữµÄÏõËáÒøÈÜÒº£¬Èç¹ûÓе­»ÆÉ«³ÁµíÉú³É£¬¾Í˵Ã÷º¬ÓÐäåÔªËØ£¬Æä¼ìÑé·½·¨ÊÇ£ºÓÃÊÔ¹ÜÁ¿È¡ÉÙÁ¿äåÒÒÍéÈÜÒº£¬È»ºóÏòÈÜÒºÖмÓÈëÇâÑõ»¯ÄƵÄË®ÈÜÒº½øÐмÓÈÈ£¬ÔÙÏòÈÜÒºÖмÓÈëÏõËáËữµÄÏõËáÒøÈÜÒº£¬¹Û²ìÊÇ·ñÓе­»ÆÉ«³ÁµíÉú³É£¬
¹Ê´ð°¸Îª£ºÓÃÊÔ¹ÜÁ¿È¡ÉÙÁ¿äåÒÒÍéÈÜÒº£¬È»ºóÏòÈÜÒºÖмÓÈëÇâÑõ»¯ÄƵÄË®ÈÜÒº½øÐмÓÈÈ£¬ÔÙÏòÈÜÒºÖмÓÈëÏõËáËữµÄÏõËáÒøÈÜÒº£¬¹Û²ìÊÇ·ñÓе­»ÆÉ«³ÁµíÉú³É£®

µãÆÀ ±¾Ì⿼²éÓлúÎïÍƶϣ¬Îª¸ß¿¼¸ßƵµã£¬Éæ¼°Ï©Ìþ¡¢´¼¡¢Â±´úÌþÖ®¼äµÄת»¯£¬Ã÷È·ÎïÖÊÖйÙÄÜÍż°ÆäÐÔÖÊÊǽⱾÌâ¹Ø¼ü£¬ÊìÁ·ÕÆÎÕ³£¼ûÓлúÎïÐÔÖÊ£¬Ò×´íµãÊÇ£¨4£©Ì⣬עÒ⻯ѧÓÃÓïµÄÕýÈ·ÔËÓã®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø